An alternating series

converges if

is monotonic and

as

. Here

.
Let

. Then

, which is positive for all

, so

is monotonically increasing for

. This would mean

must be a monotonically decreasing sequence over the same interval, and so must

.
Because

is monotonically increasing, but will still always be positive, it follows that

as

.
So,

converges.
Hi there!
Since the formula for finding the perimeter of a rectangle is length×2 + width × 2, we can follow this rule.
2 (4x + 5) + 2 (8x - 4)
= 8x + 10 + 16x - 8
= 24x + 2
So, the perimeter is 24x + 2.
Hope this helps!
Answer:
35cm²
Step-by-step explanation:
Area = trapezium + triangle
Trapezium = ½×(8+4)×2 = 12
Triangle = ½×8×5.75 = 23
Area = 12+23 = 35 cm²
Answer:
3rd option
Step-by-step explanation:
There are three wholes and 1 fourth which is 1/8 simplified so first improper fraction, CHECK!
The three wholes are all equal to 12 then there is another 1 fourth so 12+1=13 CHECK TOO!!!
(YAY WE SOLVED IT!)
A)
10.00 - 3.55 = 6.45 back
a $5 bill and a $1 dollar bill = $6
a quarter and 2 dimes = 0.45
so 2 bills and 3 coins
B) 120 x 4 = 480 minutes
480/60 = 8 hours