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Helen [10]
2 years ago
10

How will you graphically represent data in cyber security with math?

Mathematics
1 answer:
qaws [65]2 years ago
3 0

Answer:

Step-by-step explanation:

another math-based concept used in cybersecurity is hexadecimal math. Rather than having only two options, as in binary math, hexadecimal math is based on the idea that you can count up to any one of 16 different options. ... Cryptography is the science of codes and encryption and is based on mathematical theory

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Seraphina picked 120 strawberries in six hours. At this rate, how many strawberries did Seraphina pick in 4 hours?
Lyrx [107]

Answer:

80 Strawberries

Step-by-step explanation:

If she picked 120 strawberries in 6 hours

Then in 1hour she picked 120/6 = 20 strawberries

Then in 4 hours she picked 20×4 = 80 strawberries

8 0
3 years ago
Determine whether the triangles are congruent by sss sas asa aas hl
Semmy [17]

Answer:

Congruent by SAS

Step-by-step explanation:

The three given sides of one triangle is shown to be equal to the corresponding sides of the other triangle.

This means that all threes sides of one are congruent to all corresponding sides of the other triangle.

By the Side-Side-Side Congruence Theorem, we can conclude that both triangles are congruent.

7 0
3 years ago
You cut a 54-inch rope into four pieces. Twoof the pieces are the same length, a thirdpiece is twice as long as each of the twoe
antiseptic1488 [7]

Let's use the variable x to represent the length of the first and second pieces.

If the third piece has twice the length of the first and second, its length is 2x.

If the fourth piece has half the length of the first and second, its length is 0.5*x.

Adding all four pieces and equating to 54 inches, we have:

\begin{gathered} x+x+2x+0.5x=54 \\ 4.5x=54 \\ x=\frac{54}{4.5} \\ x=12 \end{gathered}

So the length of each piece is:

12 inches, 12 inches, 24 inches and 6 inches.

5 0
1 year ago
Derive the equation of the parabola with a focus at (3,1) and a directrix of y = 5
serg [7]
So hmmm  check the picture below

so... the vertex is "p" distance from the focus and the directrix, thus, the vertex is really half-way between both

in this case, 2 units up from the focus or 2 units down from the directrix, and thus it lands at 3,3

now, the "p" distance is 2, however, the directrix is up, the focus point is below it, the parabola opens towards the focus point, thus, the parabola is opening downwards, and the squared variable is the "x"

because the parabola opens downwards, "p" is negative, and thus, -2

now, let's plug all those fellows in then

\bf \begin{array}{llll}
(x-{{ h}})^2=4{{ p}}(y-{{ k}})\\
\end{array}
\qquad 
\begin{array}{llll}
vertex\ ({{ h}},{{ k}})\\
{{ p}}=\textit{distance from vertex to }\\
\qquad \textit{ focus or directrix}
\end{array}\\\\
-----------------------------\\\\

\begin{cases}
h=3\\
k=3\\
p=-2
\end{cases}\implies (x-3)^2=4(-2)(y-3)\implies (x-3)^2=-8(y-3)
\\\\\\
-\cfrac{(x-3)^2}{8}=y-3\implies \boxed{-\cfrac{1}{8}(x-3)^2+3=y}

5 0
3 years ago
An exit poll in an election is a survey taken of voters just after they have voted. One major use of exit polls has been so that
3241004551 [841]

Answer:

P(A) = 0.39

Step-by-step explanation:

We are given;

P(W|A) = 0.7

P(W|A^c ) = 0.3

We are told that 60% of the respondents said they voted for A. Thus;

P(A|W) = 60% = 0.6

Now, using the principle of drawing lots, we can be able to find the probability of the event that they are willing to participate in the exit poll which is P(W).

Thus;

P(W) = [P(W|A) × P(A)] +[P(W∣A^c) × P(A^c)]

Now, P(A^c) can be expressed as 1 - P(A)

Thus, we now have;

P(W) = [P(W|A) × P(A)] + [P(W∣A^c) × (1 - P(A)]

Plugging in the relevant values gives;

P(W) = 0.7P(A) + 0.3(1 - P(A))

P(W) = 0.7P(A) + 0.3 - 0.3P(A)

P(W) = 0.3 + 0.4P(A)

Now,using Baye's theorem, we can find an expression for P(A|W)

Thus;

P(A|W) = [P(A ∩ W)]/P(W)

This can be further expressed as;

P(A|W) = [P(A) × P(W|A)]/P(W)

Plugging in relevant values, we have;

0.6 = 0.7P(A)/(0.3 + 0.4P(A))

Cross multiply to get;

0.6(0.3 + 0.4P(A)) = 0.7P(A)

0.18 + 0.24P(A) = 0.7P(A)

0.18 = 0.7P(A) - 0.24P(A)

0.46P(A) = 0.18

P(A) = 0.18/0.46

P(A) = 0.39

7 0
3 years ago
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