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3 years ago

What is the mean of the data set? 108, 305, 252, 113, 191

Mathematics

2 answers:

Blababa [14]3 years ago

8 0

Answer:

The mean of the data set is 193.8

Step-by-step explanation:

Mean of the data set : 108, 305, 252, 113, 191

To calculate the mean add up all the numbers and then divide by the numbers of the values.

$Mean=\frac{\text{Sum of data}}{\text{Number of values}}$

Mean = $\frac{108 + 305 + 252 + 113 + 191}{5}$

Mean = $\frac{969}{5}$ = 193.8

The mean of the data set is 193.8

irinina [24]3 years ago

7 0

Go to the third pic for your answer. I got problem 4 wrong but it shows the correct answer.

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A builder of houses needs to order some supplies that have a waiting time Y for delivery, with a continuous uniform distribution

xenn [34]

Answer:

The Expected cosy of the builder is $433.3

Step-by-step explanation:

$400 is the fixed cost due to delay.

Given Y ~ U(1,4).

Calculating the Variable Cost, V

V = $0 if Y≤ 2

V = 50(Y-2) if Y > 2

This can be summarised to

V = 50 max(0,Y)

Cost = 400 + 50 max(0, Y-2)

Expected Value is then calculated by;

Waiting day =2

Additional day = at least 1

Total = 3

E(max,{0, Y - 2}) = integral of Max {0, y - 2} * ⅓ Lower bound = 1; Upper bound = 4, (4,1)

Reducing the integration to lowest term

E(max,{0, Y - 2}) = integral of (y - 2) * ⅓ dy Lower bound = 2; Upper bound = 4 (4,2)

E(max,{0, Y - 2}) = integral of (y) * ⅓ dy Lower bound = 0; Upper bound = 2 (2,0)

Integrating, we have

y²/6 (2,0)

= (2²-0²)/6

= 4/6 = ⅔

Cost = 400 + 50 max(0, Y-2)

Cost = 400 + 50 * ⅔

Cost = 400 + 33.3

Cost = 433.3

5 0

3 years ago

Read 2 more answers

Darrell flips a weighted coin 20 times and gets 4 tails. What is the experimental probability that the next flip will come up ta

Inga [223]

There is a fifty percent chance of the coin landing on "heads" each time it is flipped.

However, flipping a coin 20 times virtually guarantees that it will land on "heads" at least once in that twenty times. <span>(99.9999046325684 percent chance)
</span>
You can see this by considering two coin flips. Here are the possibilities:

Heads, heads.
Heads, tails.
Tails, tails.
Tails, heads.

You will note in the tossing of the coin twice that while each flip is fifty/fifty, that for the two flip series, there are three ways that it has heads come up at least once, and only one way in which heads does not come up. In other words, while it is a fifty percent chance for heads each time, it is a seventy five percent chance of seeing it be heads once if you are flipping twice. If you wish to know the odds of it not being heads in a twenty time flip, you would multiply .5 times .5 times .5...twenty times total. Or .5 to the twentieth power. That works out to a 99.9999046325684 percent chance of it coming up heads at least once in the twenty times of it being flipped.

8 0

3 years ago

Can you answer this for me Reward: 10 Points.

pogonyaev

Answer:

1 10/12

Step-by-step explanation:

So you would do 2x6+5 which is 17/6 then plus 1/2 x 5/6 which is 5/12 then 17/6 + 5/6 = 22/12 then divide 22 by 12 and get 1 then leftover 10 so 1 10/12.

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3 years ago

Please help! I will mark brainliest!

Scorpion4ik [409]

Answer:

Area = 48 square units

Step-by-step explanation:

You're welcome :)

5 0

3 years ago

A particular fruit's weights are normally distributed, with a mean of 738 grams and a standard deviation of 14 grams. The heavie

posledela

Answer:

We get that the heaviest of fruits weigh 766.84 grams.

Step-by-step explanation:

We know that a particular fruit's weights are normally distributed, with a mean of 738 grams and a standard deviation of 14 grams.

We have:

$\mu=738\\\\\sigma=14$

We calculate x:

$P(X$

We use the standard normal table and we get: Z=2.06.

So, we get

$2.06=\frac{x-738}{14}\\\\x-738=28.84\\\\x=766.84$

We get that the heaviest of fruits weigh 766.84 grams.

5 0

3 years ago