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tigry1 [53]
3 years ago
13

Name two locations that are the same distance apart on the map. List two pairs of locations. will give brainliest for the first

person to answer.won't give brainliest if not understandable!

Mathematics
2 answers:
never [62]3 years ago
8 0
Answer: Bumper Cars and Submarine Ride; Teacups and Parking lot.

Reasoning: Considering we go from the coordinates of the picture the distance between the pairs would be 9

Step by step:

1. Find the proper coordinates (x,y)
Submarine Ride: (-9,9)
Bumper Cars: seems to take up two coordinates we r working with it being at (-5,4)
Teacups: (-5,-2)
Parking lot: (-9,-7)

2. Find the difference between x and y and add the absolute values. The easies way to do this is by looking at the coordinates rather then counting on the graph

SR (-9,9)
BC (-5,4 )
Difference in x: 4
Difference in y: 5
Total distance : 9

TC (-5,-2)
PL (-9,-7)
Difference in x: 4
Difference in y: 5
Total distance: 9



Vikki [24]3 years ago
5 0

Answer:

pizza parlor to ferris wheel

pizza parlor to bumper cars

Step-by-step explanation:

You might be interested in
A: What are the solutions to the quadratic equation x2+9=0? B: What is the factored form of the quadratic expression x2+9? Selec
Paraphin [41]

Answer:

A. The solutions are x=3i,\:x=-3i.

B. The factored form of the quadratic expression x^2+9=(x-3i)(x+3i)

Step-by-step explanation:

A. To find the solutions to the quadratic equation x^2+9=0 you must:

\mathrm{Subtract\:}9\mathrm{\:from\:both\:sides}\\\\x^2+9-9=0-9\\\\\mathrm{Simplify}\\\\x^2=-9\\\\\mathrm{For\:}x^2=f\left(a\right)\mathrm{\:the\:solutions\:are\:}x=\sqrt{f\left(a\right)},\:\:-\sqrt{f\left(a\right)}\\\\x=\sqrt{-9},\:x=-\sqrt{-9}

x=\sqrt{-9} = \sqrt{-1}\sqrt{9}=\sqrt{9}i=3i\\\\x=-\sqrt{-9}=-\sqrt{-1}\sqrt{9}=-\sqrt{9}i=-3i

The solutions are:

x=3i,\:x=-3i

B. Two expressions are equivalent to each other if they represent the same value no matter which values we choose for the variables.

To factor x^2+9:

First, multiply the constant in the polynomial by i^2 where i^2 is equal to -1.

x^2+9i^2

Since both terms are perfect squares, factor using the difference of squares formula

a^2-i^2=(a+i)(a-i)

x^2+9=x^2+9i^2=\left(-3i+x\right)\left(3i+x\right)

5 0
3 years ago
A ball will be drawn from the bag containing 20 balls numbered one through 20 if each ball is equally likely to be drawn what is
son4ous [18]

Answer:

3/5

Step-by-step explanation:

There are 20 balls, numbered 1 through 20.

Of these, 10 are even, 4 are less than five, and 2 are both even and less than 5.

So the probability is:

P(even or <5) = P(even) + P(<5) − P(even and <5)

P(even or <5) = 10/20 + 4/20 − 2/20

P(even or <5) = 12/20

P(even or <5) = 3/5

5 0
3 years ago
Shaun needs to make mortar for brick-laying. It is made in the ratio 7:3 of sand to cement.
Tju [1.3M]
Sand to cement
7:3

210:x

ask yourself what number is needed to multiply by 7 to get 210 ( so you'd divide 210 by 7 which is 30). Multiply the other side by thirty as well to get the value of x

3*30 which is 90

7 0
3 years ago
Will Mark as brainliest!<br><br> Which figure can be formed from the net?
Mandarinka [93]
I believe it is the first figure
5 0
3 years ago
Solving the whole thing
erik [133]
Let
x---------------> distance from people living to the city center

we Know that
Zone 1 covers people living within three miles of the city center
Zone 1 ------------> [x < 3 miles]

Zone 2 covers those between three and seven miles from the center
Zone 2 ------------> [ 3 <= x < = 7  miles]

Zone 3 covers those over seven miles from the center
Zone 3 ------------> [  x > 7  miles]

<span>calculate the distance between two points to find the value of x
</span>
case A) point (0,0)  point (3,4)
x=√[(y2-y1)² +(x2-x1)²]----------> √[(4-0)² +(3-0)²]------> √[16+9]
x=√25-------------> x=5 miles

the answer Part A)
people living in (3,4)
x=5 miles -------------> covers Zone 2 [ 3 < =x <= 7  miles]


case B) point (0,0)  point (6,5)
x=√[(y2-y1)² +(x2-x1)²]----------> √[(5-0)² +(6-0)²]------> √[25+36]
x=√61-------------> x=7.81 miles

the answer Part B)
people living in (6,5) 
x=7.81 miles -------------> covers Zone 3 [  x > 7  miles]

case C) point (0,0)  point (1,2)
x=√[(y2-y1)² +(x2-x1)²]----------> √[(2-0)² +(1-0)²]------> √[4+1]
x=√5-------------> x=2.23 miles

the answer Part C)
people living in (1,2) 
x=2.23 miles -------------> covers Zone 1 [ x < 3  miles]

case D) point (0,0)  point (0,3)
x=√[(y2-y1)² +(x2-x1)²]----------> √[(3-0)² +(0-0)²]------> √[9]
x=√9-------------> x=3 miles

the answer Part D)
people living in (0,3) 
x=3 miles -------------> covers Zone 2 [ 3 < =x <= 7  miles]

case E) point (0,0)  point (1,6)
x=√[(y2-y1)² +(x2-x1)²]----------> √[(6-0)² +(1-0)²]------> √[36+1]
x=√37-------------> x=6.08 miles

the answer Part E)
people living in (1,6) 
x=6.08 miles -------------> covers Zone 2 [ 3 < = x <= 7  miles]

4 0
3 years ago
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