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andrezito [222]
3 years ago
13

A manufacturer has 5,634 pens to divide into packs of 4 pens. The manufacturer makes as many packs as possible.

Mathematics
1 answer:
Pachacha [2.7K]3 years ago
4 0

Answer:

1,408 packs can be made, and 2 pens will be left out.

Step-by-step explanation:

Given that a manufacturer has 5,634 pens to divide into packs of 4 pens, and the manufacturer makes as many packs as possible, to determine how many packs of pens does the manufacturer make, and how many pens are left over, the following must be done calculation:

5.634 / 4 = X

1,408.5 = X

5,634 - (1,408 x 4) = X

5.634 - 5.632 = X

2 = X

Therefore, 1,408 packs can be made, and 2 pens will be left out.

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Practice calculating the mean of a data set.
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Total money = 150 + 95 + 210 + 45 + 55 + 165 = $720

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What is the rule of -3,18,-108,—,—,—
lisabon 2012 [21]

Hi! ❄

   - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - -

The rule for this sequence is 'multiply by -6'.

Verification ↓

-3*(-6)\stackrel\checkmark{=}18

18*(-6)\stackrel\checkmark{=}-108

So the rule for the sequence is 'multiply by -6'

And the Common ratio is -6.

Hope that made sense !!

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5 0
2 years ago
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Find the surface area of each prism
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Answer:

Step-by-step explanation:

2.

Surface area = ( 6 *10 ) *3  + ( ( 7*4.87) /2)*2 = 180 + 34.09 = 214.09

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6 0
3 years ago
To play basketball with her friends, Evangeline needs to pump air in her ball, which is completely deflated. Before inflating it
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Answer:

ρ_air = 0.15544 kg/m^3

Step-by-step explanation:

Solution:-

- The deflated ball ( no air ) initially weighs:

                             m1 = 0.615 kg

- The air is pumped into the ball and weight again. The new reading of the ball's weight is:

                            m2 = 0.624 kg

- The amount of air ( mass of air ) pumped into the ball can be determined from simple arithmetic between inflated and deflated weights of the ball.

                           m_air = Δm = m2 - m1

                           m_air = 0.624 - 0.615

                           m_air = 0.009 kg

- We are to assume that the inflated ball takes a shape of a perfect sphere with radius r = 0.24 m. The volume of the inflated ( air filled ) ball can be determined using the volume of sphere formula:

                         V_air = 4*π*r^3 / 3

                         V_air = 4*π*0.24^3 / 3

                         V_air = 0.05790 m^3  

 

- The density of air ( ρ_air ) is the ratio of mass of air and the volume occupied by air. Expressed as follows:

                         ρ_air = m_air / V_air

                         ρ_air = 0.009 / 0.05790

Answer:            ρ_air = 0.15544 kg/m^3                      

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