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lukranit [14]
2 years ago
13

What is the approximate area of a circle with diameter 6?

Mathematics
1 answer:
BaLLatris [955]2 years ago
7 0

Answer: 28.27

Step-by-step explanation:

First, you can turn the diameter into a radius, giving you 3. Since the equation of an area in a circle is A=πr^2, you must square 3, giving you 9. Now you must multiply 9 with Pi, which is 3.14159265358, but just 3.14 for short. With that, you get about 28.27 as area.

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Use the Distributive Property to rewrite the algebraic expression. 7(6m + 7)
jeka57 [31]

Step-by-step explanation:

first, distribute 7 to 6m (this means 7 • 6m)

7 • 6m = 42m

then distribute 7 to 7 (which is 7 • 7)

7 • 7 = 49

your simplified expression is <u>42m + 49</u>. i hope this helps! have a great day <3

6 0
3 years ago
WILL MARK BRAINLIEST! PLEASE HELP!<br> Write 206 in base 7
Anna71 [15]

Answer:

413_7

Step-by-step explanation:

Convert the following to base 7:

206_10

Hint: | Starting with zero, raise 7 to increasingly larger integer powers until the result exceeds 206.

Determine the powers of 7 that will be used as the places of the digits in the base-7 representation of 206:

Power | \!\(\*SuperscriptBox[\(Base\), \(Power\)]\) | Place value

3 | 7^3 | 343

2 | 7^2 | 49

1 | 7^1 | 7

0 | 7^0 | 1

Hint: | The powers of 7 (in ascending order) are associated with the places from right to left.

Label each place of the base-7 representation of 206 with the appropriate power of 7:

Place | | | 7^2 | 7^1 | 7^0 |  

| | | ↓ | ↓ | ↓ |  

206_10 | = | ( | __ | __ | __ | )_(_7)

Hint: | Divide 206 by 7 and find the remainder. The remainder is the first digit from the right.

Determine the value of the first digit from the right of 206 in base 7:

206/7=29 with remainder 3

Place | | | 7^2 | 7^1 | 7^0 |  

| | | ↓ | ↓ | ↓ |  

206_10 | = | ( | __ | __ | 3 | )_(_7)

Hint: | Divide the whole number part of the previous quotient, 29, by 7 and find the remainder. The remainder is the next digit.

Determine the value of the next digit from the right of 206 in base 7:

29/7=4 with remainder 1

Place | | | 7^2 | 7^1 | 7^0 |  

| | | ↓ | ↓ | ↓ |  

206_10 | = | ( | __ | 1 | 3 | )_(_7)

Hint: | Divide the whole number part of the previous quotient, 4, by 7 and find the remainder. The remainder is the last digit.

Determine the value of the last remaining digit of 206 in base 7:

4/7=0 with remainder 4

Place | | | 7^2 | 7^1 | 7^0 |  

| | | ↓ | ↓ | ↓ |  

206_10 | = | ( | 4 | 1 | 3 | )_(_7)

Hint: | Express 206_10 in base 7.

The number 206_10 is equivalent to 413_7 in base 7.

Answer: 206_10 =413_7

5 0
2 years ago
Wut is 100000000000 x 0
weeeeeb [17]

Answer:

0

Step-by-step explanation:hope this helped lol hope u have a wonderful thanksgiving day!!!!!!!

4 0
3 years ago
"The product of eight and some number" can be written as:
Angelina_Jolie [31]
8n
Hope it helps, good luck
6 0
3 years ago
3/8 \ 1/4= show your work ASAP
Rashid [163]
12/8=3/2 TIMES THE OPPOSITE <span />
8 0
3 years ago
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