Help pls need for a test!

Pressure with Two Liquids, Hg and Water. An open test tube at 293 K is filled at the bottom with 12.1 cm of Hg, and 5.6 cm of wa

Radda [10]

Answer:

$1170839.28 dyn/cm^2$

16.9816 psia

$117.083928 kN/m^2$

Explanation:

To calculate the absolute pressure in the bottom of tube we need to sum the atmosferic and gauge pressure.

$P_{abs}=P_{atm}+P_G$

And the gauge pressure is given by the contributions of columns of water ( $P_{w}$ ) and mercury( $P_{Hg}$ ), we can calculate the contribution of each column as:

$P= \rho g h$ (*)

where $\rho$ is the respective density, g gravity and h is height.

So we have all the data required to use the above equations ( $P_{atm}$ , height and density of each column) we only need to be carefully with the units.

For simplicity we can to express all pressure contributions in mmHg ( $P_{atm}$ , $P_{w}$ and $P_{Hg}$ ). Note that the units "x" mmHg means the pressure at the bottom of a column of mercury of "x" mm high. For example, in this case we have a column 12.1 cm of Hg, that is a column of 121 mmHg (passing from cm to mm only requires multiply by 10) pressure exerted by that column is 121 mmHg.

Now pressure of 5.6 cm (56 mm) of water would be 56 mm of water, but it is not the same that mmHg, since the density of water is lower, the pressure exerted by 1 mm of water is lower than the exerted by 1 mm of Hg. The conversion between mmHg and mm of water is given by the relation between the densities.

$mmHg=\frac{\rho_w*mmH_2O}{\rho_{Hg}}$

$mmHg=\frac{0.998*mmH_2O}{13.55}=0.0737 mmH_2O$

And pressure of water in mmHg is

$0.0737*56=4.1246 mmHg$

The absolute pressure is:

$P_{abs}=P_{atm}+P_G= 756 + 121 + 4.1246 = 881.1246 mmHg = 88.11246cmHg$

To pass to dyn/cm^2 units we need to use the equation (*)

$P= \rho g h = 13.55 \frac{g}{cm^3} * 980.665 \frac{cm}{s^2} * 88.11246 cmHg = 1170839.28 \frac{g}{cm s^2} = 1170839.28 \frac{dyn}{cm^2}$

Note: We need to use cm Hg for units coherence

Now passing from dyn/ $cm^2$ to kN/ $m^2$ (or kPa) we need to consider that 1 dyn is $10^{-8}$ kN and 1 $cm^2$ is $10^{-4} m^2$ .

$1170839.28 \frac{dyn}{cm^2} * \frac{10^{-8}kN}{1 dyn}*\frac{cm^2}{10^{-4}m^2}=117.083928kN/m^2$

Now passing kN/ $m^2$ to psia. We need to consider that 1 psia is 6.89476.

$117.083928kN/m^2*\frac{1psia}{6.89476kN/m^2}=16.9816 psia$

8 0

3 years ago

X-Mart purchased $300 of merchandise on account. Demonstrate the journal entry to record this transaction, assuming the perpetua

pav-90 [236]

Answer:

See explanation

Explanation:

Since X-Mart company uses perpetual inventory system, the inventory system shows the real-time selling of inventories. Purchasing merchandise on account means no cash has been paid and a liability is existed. To record the transaction, the following journal entry will require in the book of X-Mart-

Debit Merchandise Inventory $300

Credit Accounts payable $300

3 0

3 years ago

Read 2 more answers

Present Value of Ordinary Annuity Period/Rate 5% 6% 7% 8% 9% 10 7.7217 7.3601 7.0236 6.7101 6.4177 11 8.3064 7.8869 7.4987 7.139

klasskru [66]

Answer:

The discount rate of 8% for 11 year period provides the present value of annual cash flows to be equal to the initial investment.

Explanation:

Using the table of present value of annuity provided, we can check the rate and time period which is return the present value of cash flows from the project to be equal to initial Investment.

We are told that the Project's life is expected to be 11 Years. Thus using the 11 year period from the table we can see the following rates,

11 Year Period

Rate = 5% , Annuity Factor = 8.3064

Rate = 6% , Annuity Factor = 7.8869

Rate = 7% , Annuity Factor = 7.4987

Rate = 8% , Annuity Factor = 7.1390

Rate = 9% , Annuity Factor = 6.8052

We know that the annual cash flows from the project is $1,000,000 and we know the Initial Outlay is $7,139,000.

Multiplying the annual cash flow from the above annuity factors for each rate we can see which rate provides the present value of annual cash flows to be equal to initial outlay.

Rate = 5% , Present value = 8.3064 * 1000000 = $8,306,400

Rate = 6% , Annuity Factor = 7.8869 * 1000000 = $7,886,900

Rate = 7% , Annuity Factor = 7.4987 * 1000000 = $7,498,700

Rate = 8% , Annuity Factor = 7.1390 * 1000000 = $7,139,000

Rate = 9% , Annuity Factor = 6.8052 * 1000000 = $6,805,200

From the above calculation we can see that the rate of 8% provides the present value of annual cash flows to be equal to the initial investment.

7 0

3 years ago

Taunton's is an all-equity firm that has 152,000 shares of stock outstanding. The CFO is considering borrowing $245,000 at 6 per

dezoksy [38]

Answer:

The value of the firm is $1,773,333

Explanation:

Calculation of Value of each share

Amount borrowed (A) $245,000

No. of shares repurchased (B) 21,000

Value for each share (C) $11.67

No. of shares outstanding after repurchase(A) 131,000

(152,000 - 21,000)

Value for each share(B) $11.67

Equity value after repurchase(A*B) $1,528,333

Add: Amount borrowed $245,000

Firm value after this transaction $1,773,333

7 0

3 years ago

Bartosiewicz Clinic uses client-visits as its measure of activity. During January, the clinic budgeted for 3,100 client-visits,

Degger [83]

Answer:

$354 Favorable

Explanation:

Net Operating Income in Planned budget = Revenue - Total Expense

Net Operating Income in Planned budget = (3,100*$35.10) - (3,100*$17.40 + $44,400)

Net Operating Income in Planned budget = $108,810 - $98,340

Net Operating Income in Planned budget = $10,470

Net Operating Income in Flexible budget = Revenue - Total Expense

Net Operating Income in Flexible budget = (3,080*$35.10) - (3,080*$17.40 + $44,400)

Net Operating Income in Flexible budget = $108,108 - $97,992

Net Operating Income in Flexible budget = $10,116

Activity variance for net operating income = Net Operating Income in Planned budget - Net Operating Income in Flexible budget

Activity variance for net operating income = $10,470 - $10,116

Activity variance for net operating income = $354 Favorable

7 0

3 years ago