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Nutka1998 [239]
3 years ago
9

What are the zeros of the function f(x)= x^2-144

Mathematics
1 answer:
Margaret [11]3 years ago
8 0

Answer:

x = 12, x = -12, those are the two zeros for the equation

Step-by-step explanation:

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3 years ago
Subtract -2x^2+4x-1−2x
vivado [14]

Answer:

8x²- x -8

Step-by-step explanation:

The question is not well written. I guess what you mean is:

Subtract -2x^2+4x-1 ( minus 2x squared plus 4x minus 1) from 6x^2+3x-9 (6x squared plus 3x minus 9).

To  subtract -2x^2+4x-1 from 6x^2+3x-9, that is

6x^2+3x-9 - (-2x^2+4x-1). This can be written as

6x²+3x-9 - (-2x²+4x-1)

Now, opening the bracket, we will get

6x²+3x-9 +2x²-4x+1

Then, collecting like terms, we get

6x²+2x²+3x-4x-9+1

6x²+2x² = 8x²

3x-4x = -x

-9+1 = -8

∴6x²+2x²+3x-4x-9+1 becomes

8x²-x -8

The answer is 8x²-x -8.

7 0
3 years ago
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