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2 years ago

How can the scaling of a line graph be used to mislead a reader?

1 answer:

5 0

Misleading may be present even though all graphs may share the same data, and even the slope of the data is the same. If the way the data is plotted is not correct, it can change the visual appearance of the angle made by the line on the graph. This is so because each plot has different scales on its vertical axis. As the scales are not correctly shown then there is where the misleading appears.

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A supermarket had bags of red grapes for $13.00 for 5 bags. They also had bags of green grapes priced at $5.08 for 2 bags. Which

Sedbober [7]

Answer:

Red grapes.

Step-by-step explanation:

If you find how much one bag of each grape cost which is:

$13.00 ÷ 5 = 2.60 (1 bag of red grapes)

$5.08 ÷ 2 = $2.54 (1 bag of green grapes)

See the price and you'll know it is red grapes.

5 0

2 years ago

Is the following relation a function? (-2,3) (0,1) (5,3) (5,8) (7,5)

Rashid [163]

No it is not because for the x value of 5 there are two different y values.

5 0

3 years ago

PLEASE ANSWER ASAP FOR BRAINLEST!!!!!!!!!!!!!!!!

ANTONII [103]

Step-by-step explanation:

the answer for that question is letter D

7 0

2 years ago

Read 2 more answers

Need help please! What are the measurements of angles 1 & 2

kipiarov [429]

1 42.5* and 3 95*, the sum of all the angles =360*, so Angle J = L and M=K, Angle 1 =M/2

7 0

2 years ago

A metal cylinder can with an open top and closed bottom is to have volume 4 cubic feet. Approximate the dimensions that require

Aleksandr-060686 [28]

Answer:

$r\approx 1.084\ feet$

$h\approx 1.084\ feet$

$\displaystyle A=11.07\ ft^2$

Step-by-step explanation:

Optimizing With Derivatives

The procedure to optimize a function (find its maximum or minimum) consists in :

Produce a function which depends on only one variable
Compute the first derivative and set it equal to 0
Find the values for the variable, called critical points
Compute the second derivative
Evaluate the second derivative in the critical points. If it results positive, the critical point is a minimum, if it's negative, the critical point is a maximum

We know a cylinder has a volume of 4 $ft^3$ . The volume of a cylinder is given by

$\displaystyle V=\pi r^2h$

Equating it to 4

$\displaystyle \pi r^2h=4$

Let's solve for h

$\displaystyle h=\frac{4}{\pi r^2}$

A cylinder with an open-top has only one circle as the shape of the lid and has a lateral area computed as a rectangle of height h and base equal to the length of a circle. Thus, the total area of the material to make the cylinder is

$\displaystyle A=\pi r^2+2\pi rh$

Replacing the formula of h

$\displaystyle A=\pi r^2+2\pi r \left (\frac{4}{\pi r^2}\right )$

Simplifying

$\displaystyle A=\pi r^2+\frac{8}{r}$

We have the function of the area in terms of one variable. Now we compute the first derivative and equal it to zero

$\displaystyle A'=2\pi r-\frac{8}{r^2}=0$

Rearranging

$\displaystyle 2\pi r=\frac{8}{r^2}$

Solving for r

$\displaystyle r^3=\frac{4}{\pi }$

$\displaystyle r=\sqrt[3]{\frac{4}{\pi }}\approx 1.084\ feet$

Computing h

$\displaystyle h=\frac{4}{\pi \ r^2}\approx 1.084\ feet$

We can see the height and the radius are of the same size. We check if the critical point is a maximum or a minimum by computing the second derivative

$\displaystyle A''=2\pi+\frac{16}{r^3}$

We can see it will be always positive regardless of the value of r (assumed positive too), so the critical point is a minimum.

The minimum area is

$\displaystyle A=\pi(1.084)^2+\frac{8}{1.084}$

$\boxed{ A=11.07\ ft^2}$

8 0

2 years ago