Solution:
Given:
![V=16300(0.94)^t](https://tex.z-dn.net/?f=V%3D16300%280.94%29%5Et)
The value of a car after t - years will depreciate.
Hence, the equation given represents the value after depreciation over t-years.
To get the rate, we compare the equation with the depreciation formula.
![\begin{gathered} A=P(1-r)^t \\ \text{where;} \\ P\text{ is the original value} \\ r\text{ is the rate} \\ t\text{ is the time } \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20A%3DP%281-r%29%5Et%20%5C%5C%20%5Ctext%7Bwhere%3B%7D%20%5C%5C%20P%5Ctext%7B%20is%20the%20original%20value%7D%20%5C%5C%20r%5Ctext%7B%20is%20the%20rate%7D%20%5C%5C%20t%5Ctext%7B%20is%20the%20time%20%7D%20%5Cend%7Bgathered%7D)
Hence,
![\begin{gathered} V=16300(0.94)^t \\ A=P(1-r)^t \\ \\ \text{Comparing both equations,} \\ P=16300 \\ 1-r=0.94 \\ 1-0.94=r \\ r=0.06 \\ To\text{ percentage,} \\ r=0.06\times100=6\text{ \%} \\ \\ \text{Hence, } \\ P\text{ is the purchase price} \\ r\text{ is the rate} \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20V%3D16300%280.94%29%5Et%20%5C%5C%20A%3DP%281-r%29%5Et%20%5C%5C%20%20%5C%5C%20%5Ctext%7BComparing%20both%20equations%2C%7D%20%5C%5C%20P%3D16300%20%5C%5C%201-r%3D0.94%20%5C%5C%201-0.94%3Dr%20%5C%5C%20r%3D0.06%20%5C%5C%20To%5Ctext%7B%20percentage%2C%7D%20%5C%5C%20r%3D0.06%5Ctimes100%3D6%5Ctext%7B%20%5C%25%7D%20%5C%5C%20%20%5C%5C%20%5Ctext%7BHence%2C%20%7D%20%5C%5C%20P%5Ctext%7B%20is%20the%20purchase%20price%7D%20%5C%5C%20r%5Ctext%7B%20is%20the%20rate%7D%20%5Cend%7Bgathered%7D)
Therefore, the value of this car is decreasing at a rate of 6%. The purchase price of the car was $16,300.
Answer:
4.results should be reported with some measure that represent how convinced we are that our conclusion reflect reality
Step-by-step explanation:
Certainly statistics deals with organization, evaluation and data conclusions. But the data is always obtained from representative samples of certain universes for that reason those results must be associated with the degree of confidence
The only thing you can do with this expression is to factor a 5 out of the two terms: we have
![15n-20 = 5(3n-4)](https://tex.z-dn.net/?f=15n-20%20%3D%205%283n-4%29)
So to fine slope you would use the formula down below:
rise/run
So use a graphed point, 0, -5 and you rise or count up quadrants up to a point and then horizontally move to when you find that point.
So from 0,-5 go up 9 vertically, and you would be on the 4
Go horizontal 3 spots and your on a designated point.
So the rise is four and the run is 3
So 4/3 is the slope
In the y= Mx + b equation you would set the equation like this:
y= 4/3 + -5
The m in this formula stands for the slop and the b stands for the y-intercept
The y-intercept is the point that is on the y-axis and where it starts.