Given :
Challenge given is to volunteer for about 1 1/2 hours per week .
Autum did at a rate of 6 3/4 hours per week .
To Find :
The comparison ( ratio ) her volunteers rate with the challenge rate .
Solution :
Simplifying challenge rate in in normal fraction , 
.
Also , simplifying her rate , 
.
Now , ratio of his work by challenge is :
Therefore , the ratio is 9/2 or 4 1/2 .
Hence , this is the required solution .
I believe the answer is -6.3
my explanation is because -6.3 is less than -6.1 so technically it makes it smaller. if you were to add to -6.3 you would get -6.1 on the x axis.
Let,
- Mass of the steel be 108x
- Mass of the copper be 7x
- Then, Total mass = 108x + 7x = 115x
Given,
- Total mass of the coin = 230 mg
That means,
⇛ Total mass of the coin = 230 mg
⇛ 115x = 230 mg
⇛ x = 230 mg/115
⇛ x = 2 mg
Then,
- Mass of the steel = 108(2) = 216 mg
- Mass of the copper = 7(2) = 14 mg
☁️ ANSWER - 14 mg (Mass of copper)
<u>━━━━━━━━━━━━━━━━━━━━</u>
40$. 7hrs
X$. 1hr
X=40•1/7
X~5.71 $ per hour
