Is parallel to 3x-5y=7 and passes through (0,-6)

Jonathan buys two baseball bats for $43 each they are on sale for 45% off he also bought a glove that was originally priced at 2

vladimir2022 [97]

Hi There!

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Baseball Bats:

43 x 0.45 = $19.35 as the amount off.

43 - 19.35 = $23.65 with the discount.

23.65 x 2 = $47.3 for two bats.

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Glove:

28 x 0.25 = $7 as the amount off.

28 - 7 = $21 with the discount.

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Together:

21 + 47.3 = $68.3 as the total before taxes.

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With Taxes:

68.3 x 0.055 = $3.7565 as the tax amount.

68.3 - 3.7565 = $64.5435

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Answer:

Not Rounded: $64.5435

Rounded: $64.54

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Hope This Helps :)

3 0

2 years ago

Kyra wants to make the area of her rectangular closet 9 times larger than the size it currently is. What scale factor should she

romanna [79]

Answer:

choice 3) scale factor of 3

Step-by-step explanation:

3 times length + 3 times width = 9 times area

5 0

2 years ago

How to differentiate ?

Bas_tet [7]

Use the power, product, and chain rules:

$y = x^2 (3x-1)^3$

• product rule

$\dfrac{\mathrm dy}{\mathrm dx} = \dfrac{\mathrm d(x^2)}{\mathrm dx}\times(3x-1)^3 + x^2\times\dfrac{\mathrm d(3x-1)^3}{\mathrm dx}$

• power rule for the first term, and power/chain rules for the second term:

$\dfrac{\mathrm dy}{\mathrm dx} = 2x\times(3x-1)^3 + x^2\times3(x-1)^2\times\dfrac{\mathrm d(3x-1)}{\mathrm dx}$

• power rule

$\dfrac{\mathrm dy}{\mathrm dx} = 2x\times(3x-1)^3 + x^2\times3(3x-1)^2\times3$

Now simplify.

$\dfrac{\mathrm dy}{\mathrm dx} = 2x(3x-1)^3 + 9x^2(3x-1)^2 \\\\ \dfrac{\mathrm dy}{\mathrm dx} = x(3x-1)^2 \times (2(3x-1) + 9x) \\\\ \boxed{\dfrac{\mathrm dy}{\mathrm dx} = x(3x-1)^2(15x-2)}$

You could also use logarithmic differentiation, which involves taking logarithms of both sides and differentiating with the chain rule.

On the right side, the logarithm of a product can be expanded as a sum of logarithms. Then use other properties of logarithms to simplify

$\ln(y) = \ln\left(x^2(3x-1)^3\right) \\\\ \ln(y) = \ln\left(x^2\right) + \ln\left((3x-1)^3\right) \\\\ \ln(y) = 2\ln(x) + 3\ln(3x-1)$

Differentiate both sides and you end up with the same derivative:

$\dfrac1y\dfrac{\mathrm dy}{\mathrm dx} = \dfrac2x + \dfrac9{3x-1} \\\\ \dfrac1y\dfrac{\mathrm dy}{\mathrm dx} = \dfrac{15x-2}{x(3x-1)} \\\\ \dfrac{\mathrm dy}{\mathrm dx} = \dfrac{15x-2}{x(3x-1)} \times x^2(3x-1)^3 \\\\ \dfrac{\mathrm dy}{\mathrm dx} = x(15x-2)(3x-1)^2$