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eduard
3 years ago
9

Pls help plz plz plz dont be mean

Mathematics
1 answer:
Minchanka [31]3 years ago
7 0

Answer:

it lets me watch p.orn in my computer

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5. 4inch
6. 6cm
7. Cannot tell
8. 50mm
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10. 1.5cm
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3 years ago
I will give you brainliest if you solve the math question
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Answer:

<em>y</em><em>=</em><em> </em><em>125</em><em>°</em>

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quester [9]
The answer would be 28 feet, to get area you do length times width, 7 x 4 = 28
7 0
3 years ago
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Find the components of the vertical force Bold Upper Fequalsleft angle 0 comma negative 8 right anglein the directions parallel
nydimaria [60]

Answer with Step-by-step explanation:

We are given that

F=<0,-8>=0i-8j=-8j

\theta=\frac{\pi}{3}

The component of force is divided into two direction

1.Along the plane

2.Perpendicular to the plane

1.The vector parallel to the plane will be=r=cos\frac{\pi}{3}i-sin\frac{\pi}{3}j=\frac{1}{2}i-\frac{\sqrt 3}{2}j

By using cos\frac{\pi}{3}=\frac{1}{2},sin\frac{\pi}{3}=\frac{\sqrt 3}{2}

Force along the plane will be=\mid F_x\mid=F\cdot r

Force along the plane will be =\mid F_x\mid=F\cdot (\frac{1}{2}i-\frac{\sqrt 3}{2}j)=-8j\cdot(\frac{1}{2}i-\frac{\sqrt 3}{2}j)=8\times \frac{\sqrt 3}{2}=4\sqrt 3N

By using i\cdot i=j\cdoty j=k\cdot k=1,i\cdot j=j\cdot k=k\cdot i=j\cdot i=k\cdot j=i\cdot k=0

Therefore, force along the plane=\mid F_x\mid(\frac{1}{2}i-\frac{\sqrt 3}{2}j)=4\sqrt 3(\frac{1}{2}i-\frac{\sqrt 3}{2}j)

2.The vector perpendicular to the plane=r=-sin\frac{\pi}{3}-cos\frac{\pi}{3}=-\frac{\sqrt 3}{2}i-\frac{1}{2}j

The force perpendicular to the plane=\mid F_y\mid=F\cdot r=-8j(-\frac{\sqrt 3}{2}i-\frac{1}{2}j)

The force perpendicular to the plane=4N

Therefore, F_y=4(-\frac{\sqrt 3}{2}i-\frac{1}{2}j)

Sum of two component of force=F_x+F_y=4\sqrt 3(\frac{1}{2}i-\frac{\sqrt 3}{2}j)+4(-\frac{\sqrt 3}{2}i-\frac{1}{2}j)

Sum of two component of force=2\sqrt 3i-6j-2\sqrt3 i-2j=-8j

Hence,sum of two component of forces=Total force.

6 0
3 years ago
Does anyone know 8-10?
Anon25 [30]
#8).
The volume of a cone is      (1/3) (pi) (radius of the round end)² (height)

That's the volume of the ice cream cone alone.

The volume of a sphere is    (4/3) (pi) (radius)³

The glob of ice cream on top is 1/2 of a sphere.
The sphere and the cone in this problem both have the same radius.

#9).
The volume of a cylinder is        (pi) (radius of the round end)² (height)

#10).
Another cylinder !
The volume of a cylinder is        (pi) (radius of the round end)² (height)


8 0
3 years ago
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