The number of DVDs that will be checked out for every 100 patrons will be 20.
<h3>How to find that a given condition can be modeled by binomial distribution?</h3>
Binomial distributions consist of n independent Bernoulli trials.
Bernoulli trials are those trials that end up randomly either on success (with probability p) or on failures( with probability 1- p = q (say))
Suppose we have random variable X pertaining to a binomial distribution with parameters n and p, then it is written as

The probability that out of n trials, there'd be x successes is given by

The expected value of X will be:

The information is given in the table.
The probability of getting DVDs will be

The value of n is 100.
Then the number of DVDs that will be checked out for every 100 patrons will be

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Answer:
(x) = 
Step-by-step explanation:
let y = h(x) and rearrange making x the subject, that is
y =
x + 12 ( multiply through by 4 to clear the fraction )
4y = 3x + 48 ( subtract 48 from both sides )
4y - 48 = 3x ( divide both sides by 3 )
= x
Change y back into terms of x, thus
(x) = 
Answer and Explanation:
Using trig ratios, we can express the given values of sin u and tan v as shown below
![\begin{gathered} \sin u=\frac{opposite\text{ of angle u}}{\text{hypotenuse}}=\frac{2}{5} \\ \tan v=\frac{opposite\text{ of angle v}}{\text{hypotenuse}}=\sqrt[]{21} \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20%5Csin%20u%3D%5Cfrac%7Bopposite%5Ctext%7B%20of%20angle%20u%7D%7D%7B%5Ctext%7Bhypotenuse%7D%7D%3D%5Cfrac%7B2%7D%7B5%7D%20%5C%5C%20%5Ctan%20v%3D%5Cfrac%7Bopposite%5Ctext%7B%20of%20angle%20v%7D%7D%7B%5Ctext%7Bhypotenuse%7D%7D%3D%5Csqrt%5B%5D%7B21%7D%20%5Cend%7Bgathered%7D)
So we can go ahead and label the sides of the triangle as shown below;
We can find the value of u as shown below;

We can find v as shown below;
Answer:
answer mine i will answer yours
Step-by-step explanation:
Answer:
43
Step-by-step explanation: