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Basile [38]
2 years ago
5

Factor -2x^3+8x^2-8x​

Mathematics
1 answer:
Lady bird [3.3K]2 years ago
4 0

Step-by-step explanation:

-2x³ + 8x² - 8x

= -2x(x² - 4x + 4)

= -2x(x - 2)².

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Can someone solve this?
Gemiola [76]

Answer:

B : 4x\sqrt{17}

Step-by-step explanation:

If you divide a rhombus using its diagonals, you get 4 right triangles, whose legs are both 1/2 the length of the diagonals.

This means that the legs of one of those 4 triangles have lengths of 2x/2, and 8x/2, so the legs of one of those triangles x and 4x. This makes the length of one side equal to \sqrt{x^{2} + (4x)^{2}} = \sqrt{17x^2} = x\sqrt{17}. Because all 4 sides are the same length, you multiply this value by 4, and get 4x\sqrt{17}, which is B.

4 0
3 years ago
Determine the slope of each of the given lines.
nikitadnepr [17]
Can’t determine slop there is no picture of lines
4 0
3 years ago
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I need help ☝️ urgent please hurry up man
muminat

Answer:

J) 110.88 mm^2

Step-by-step explanation:

height =6.93x2=13.86

Area=13.86x16x0.5=110.88

7 0
3 years ago
If Victor were to put apples in bags so that there were 2 kg in each, then he would use 9 more bags than if he were to place 3 k
Cerrena [4.2K]
Let the number of bags that he would have been used to put 3 kg of apples be x. Thus the number of bags that would be used to put 2kgs will therefore be (x+9), hence the total number of kgs the bags will hold will be given by:
3*x=3x kgs
2(x+9)=(2x+18) kgs
since the total weights are the same then:
2x+18=3x
hence
18=3x-2x
18=x
thus the number of bags required to put 3 kgs of apples will be 18. Thus the total Kgs of apples was:
3x
=3*18
=54 kgs
8 0
3 years ago
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If a die is rolled one time, find probability of getting a number greater than 3 and an odd number.
Nadya [2.5K]

Answer:

\dfrac{1}{6}.

Step-by-step explanation:

It is given that a die is rolled one time. So,

Sample space : S=\{1,2,3,4,5,6\}

Number is greater than 3 : A=\{4,5,6\}

Number is odd : A=\{1,3,5\}

Number greater than 3 and an odd number : A\cap B=\{5\}

It is conclude that,

n(S)=6, n(A)=3,n(B)=3,n(A\cap B)=1

The probability of getting a number greater than 3 and an odd number is

P=\dfrac{n(A\cap B)}{n(S)}

P=\dfrac{1}{6}

Therefore, the required probability is \dfrac{1}{6}.

4 0
3 years ago
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