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3 years ago

Given a circle with an 8" radius, find the area of the smaller segment whose chord is 8" long

Mathematics

1 answer:

OLEGan [10]3 years ago

7 0

Answer:

the area of the smaller segment is 32π/3-16√3.

Step-by-step explanation:

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A rectagle has a height of 5x and a width of x+2 area=???

astra-53 [7]

Answer: $Area=5x^2+10x$

Step-by-step explanation:

The area of a rectangle:

$a=h$ × $w$

$a=5x(x+2)$

$a=5x$ × $x+5x$ × $2$

$a=5x^2+10x$

-Result:

$a=5x^2+10x$

5 0

3 years ago

Please help! If possible, please word your explanation simply.

Nesterboy [21]

Answer: It is because if ∠N and ∠K are congruent and are same in size and shape.

8 0

3 years ago

Read 2 more answers

[2.5+ 0.187]x10 please help me

MAVERICK [17]

The answer will turn out to be 26.87

6 0

3 years ago

Farmers Bob ,Joe and Larry sold apples at the farmers market .Bob sold 86 apples .Joe sold 12 times as many as Bob .Larry sold h

kotykmax [81]

Answer:

Altogether they sell 1634 apples.

Step-by-step explanation:

GIven:

Bob, Joe and Larry sold apples at the farmers market.

Bob sold 86 apples.

Joe sold 12 times as many as Bob.

Larry sold half as many apples as Joe.

Now, to find the total apples Bob, Joe and Larry they all sell together.

Number of apples Bob sold = 86.

Number of apples Joe sold = 12 times of 86.

$=12\times 86\\\\=1032.$

Number of apples Larry sold = $\frac{1}{2}\ of\ 1032$

$=\frac{1}{2} \times 1032$

$=516.$

Now, to get the apples they sell altogether we add the number of apples sold by Bob, by Joe and by Larry:

$86+1032+516$

$=1634.$

Therefore, altogether they sell 1634 apples.

7 0

3 years ago

The distance between two schools,A and B is 2 km.A market is situated a third of the distance from A to B.How far is the market

bekas [8.4K]

Answer:

$\frac{4}{3}$

Step-by-step explanation:

Find distance between B and market: |B-M|=|M-B|

Distance between A and B: $|A-B| = 2$ , call this equation (1)

Distance between A and market $|A-M| = \frac{1}{3} |A-B|=\frac{2}{3}$ , call this equation (2)

Solve (1) - (2)

$|A-B-A+M| = 2-\frac{2}{3} \\|M-B|=|B-M|=\frac{4}{3}$

3 0

3 years ago