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3 years ago

11

Find the value of 3(5. 10 + 2).

2 answers:

Mrac [35]3 years ago

5 0

Answer:

3(5. 10+2)

Step-by-step explanation:

3(5.12)

3(60)

180

-Dominant- [34]3 years ago

3 0

Answer:

the value is

Step-by-step explanation:

<em>=</em><em>3</em><em>(</em><em>5</em><em>.</em><em>1</em><em>0</em><em>+</em><em>2</em><em>)</em>

<em>=</em><em>3</em><em>(</em><em>7</em><em>.</em><em>1</em><em>)</em>

<em>=</em><em>2</em><em>1</em><em>.</em><em>3</em>

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16.

Step-by-step explanation:

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3 years ago

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A quadrilateral has two angles that measure 222° and 81°. The other two angles are in a ratio of 6:13. What are the measures of

hram777 [196]

$\sf\huge\underline{\star Solution:-}$

$\rightarrow$ <u>Ratio of two angles are 6:13.</u>

So, let the one angle be $\sf{6x}$ and another be $\sf{13x.}$

As we know that,

Sum of all interior angles of a quadrilateral = $\sf\pink{360°.}$

So let's sum up the given angles,

$\rightarrow$ $\sf{222°+81°+6x+13x \:=\: 360°}$

$\rightarrow$ $\sf{303+19x \:=\: 360°}$

$\rightarrow$ $\sf{19x \:=\: 360-303}$

$\rightarrow$ $\sf{19x \:=\: 57}$

$\rightarrow$ $\sf{x \:=\: \frac{19}{57}}$

$\rightarrow$ $\sf{x \:=\: 3}$

Hence, $\sf{x \:=\: 3}$

So, First angle $\sf{= \:6x\: = \:6×3 \:=}$ $\sf\purple{18°.}$

Second angle $\sf{= \:13x\: = \:13×3 \:=}$ $\sf\purple{39°.}$

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3 years ago

Estimate and then solve 8,784 ÷ 61 = ___.

Mnenie [13.5K]

Answer:

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2 years ago

The point P(8, −3) lies on the curve y = 3/(7 − x). (a) If Q is the point (x, 3/(7 − x)), use your calculator to find the slope

yan [13]

Answer:

Slope of the line $PQ is -63.434948.$

Step-by-step explanation:

Given that,

The point $P(8,-3)$ lies on the curve $y=\frac{3}{7-x}$ .

If $Q$ is the point lies on $(x,\frac{3}{7-x} )$ .

To find:- Find the slope of line $PQ$ .

So,

The coordinates of point $Q$ when it lies on $(x,\frac{3}{7-x} )$

if $x=1$ then $y= \frac{3}{7-1} =\frac{3}{6} =\frac{1}{2}$

So, $Q$ ≡ $(1,\frac{1}{2} )$ and many points can be calculated by given Equation.

Using the formula when two points $(x_{1} ,y_{1} ) \& (x_{2}, y_{2} )$ .

$Slope=Tan\theta = \frac{y_{2}-y_{1} }{x_{2}-x_{1} }$

Then, substituting the coordinates we get,

$Slope = \frac{1-8}{\frac{1}{2}-(-3) }$

$Slope = \frac{-7}{\frac{1}{2}+3 } = \frac{-7}{\frac{7}{2} }$

$Slope = \frac{-14}{7}=-2$

$tan\theta=-2$ ⇒ $\theta = tan^{-1} (-2)$

$\theta= -63.434948$

Therefore,

Slope of the line $mPQ is -63.434948.$

7 0

3 years ago