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sdas [7]
3 years ago
11

Which equation is represented by the graph?

Mathematics
1 answer:
Scorpion4ik [409]3 years ago
7 0
Answer: D, using rise over run the graph goes up 1 over 3 and the graph crosses the y-axis at -4 put that in y=mx+b and you get y=1/3x+-4
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NEED SOME HELP PLZZZ 30 points!!!!!!!!!
Natali [406]

Answer: i’ll help

Step-by-step explanation:

6 0
3 years ago
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Order the following values from least to greatest.
maks197457 [2]

Answer:

-6 1/2

-1

0

9

these are in order from least to greatest

3 0
3 years ago
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A movie theater charges $15 for standard viewing, $20 for 3D viewing, and $35 for Dinner and a
Ludmilka [50]

The quantity of each type of seats sold are as follows:

  • Standard viewing = 2000

  • 3D seats = 800

  • Movie and a dinner seat = 200

According to the question,there are four times as many 3D, x seats as Dinner and a Movie, y seats.

That is, x = 4y

Also, total seats

= (x) + (y) + (z) = 3000...….............eqn(1)

Also, If the theater brings in $53,000 when tickets to all 3000 seats are sold.

  • 20x + 35y + 15z = 53000...........eqn(2)

By substituting 4y for x in equations 1 and 2; we have;

<em>5y + z = 3000</em>..…........eqn(3) and

<em>115y + 15z = 53000</em>.........eqn(4)

By solving equations 3 and 4 simultaneously; we have;

y = 200 and z = 2000

and since x = 4y

x = 800

The quantity of each type of seats sold is as follows:

  • Standard viewing = 2000

  • 3D seats = 800

  • Movie and a dinner seat = 200

Read more:

brainly.com/question/12413726

5 0
3 years ago
HOW DO I SOLVE THIS??<br> What would the answer be??<br> THANKS!
Arisa [49]
Convert 300% into decimals. So move the decimal point 2 times to the left and you get 3.00 and multiply it by 5 and square it because area of square is s^2
7 0
4 years ago
Find all solutions of each equation on the interval 0 ≤ x&lt;2π.
Aleksandr [31]

Answer:

x = 0 \: or \:x =   \pi

Step-by-step explanation:

The given equation is

\tan^{2} (x) \sec^{2} (x)  + \sec^{2} (x)  - \tan^{2} (x) =  2

Subtract 2 from both sides and factor by grouping to get:

\sec^{2} (x)(\tan^{2} (x) + 2)  -1( \tan^{2} (x)  +  2)

(\tan^{2} (x) + 2) (\sec^{2} (x) - 1) = 0

By the zero product principle:

(\tan^{2} (x) + 2) = 0 \: or \:  (\sec^{2} (x) - 1) = 0

(\tan^{2} (x)  =  - 2 \: or \:  \sec^{2} (x)  =  1

When

\sec^{2} (x)  =  1 \implies\cos^{2} (x)  =  1

\implies \:  \cos(x)  =  \pm1

This implies

x = 0 \: or \:x =   \pi

When

{ \tan }^{2} (x) =  - 2

We have

\tan(x)  =  \pm \sqrt{ - 2}

hence x is not defined for all real numbers

6 0
3 years ago
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