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Leokris [45]
2 years ago
6

What is the equation in slope intercept form of the line that passes through the point(5,0)and is parallel to the line represent

ed by y=1.2x+3.8
Mathematics
2 answers:
Diano4ka-milaya [45]2 years ago
7 0

Answer:

1.2x-6

Step-by-step explanation:

Masteriza [31]2 years ago
5 0

Answer:

Step-by-step explanation:

y - 0 = 1.2(x - 5)

y = 1.2x - 6

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Slope-Intercept Form: y = <span><span><span>8/3</span>x </span>+ <span><span>−5/</span><span>3</span></span></span>
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Is sqrt(1 - sin^2 θ) = cos θ true? if so, in which quadrants does angle θ terminate?​
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Answer:

  I and IV

Step-by-step explanation:

Since 1-sin(θ)² = cos(θ)², the given equation is equivalent to ...

  √(cos(θ)²) = |cos(θ)| = cos(θ)

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Write the coordinates of the point 2 units up of the point (-5,7)
babymother [125]

Answer:

(-5,9)

Step-by-step explanation:

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3 0
3 years ago
Please help please please
Marina CMI [18]

Answer:

C. y = 2x + 8

Step-by-step explanation:

✔️First, find the slope of the line that goes through points (-2, 4) and (6, 20):

Slope (m) = ∆y/∆x = (20 - 4) / (6 - (-2))

Slope (m) = 16/8

m = 2

✔️Find the y-intercept (b):

To do this, substitute (x, y) = (6, 20) and m = 2 into y = mx + b

Thus:

20 = 2(6) + b

20 = 12 + b

20 - 12 = b

8 = b

b = 8

✔️Write the equation by substituting m = 2 and b = 8 into y = mx + b

Thus:

y = 2x + 8

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