All categories

2 years ago

The product of -6 and a number increased by 2 is -40. Find the number.

Mathematics

1 answer:

Elan Coil [88]2 years ago

4 0

The answer is -8 I know this as well as

You might be interested in

A spinner travels around a circle. The radius is 3 inches. Mike spins the spinner and it travels completely around the circle 5

nignag [31]

Answer:

The spinner travelled 94.2 inches.

Step-by-step explanation:

In order to solve this question we first need to calculate the length of the circle, that is given by the following formula:

length = 2*pi*r

length = 2*3.14*3 = 18.84 inches

Since the spinner revolved around the circle 5 times, the distance travelled by the tip is the length of the circle multiplied by 5, as shown below:

distance = length*5

distance = 18.84*5 = 94.2 inches

The spinner travelled 94.2 inches.

7 0

2 years ago

Read 2 more answers

How many times does 42 go into 136?

ludmilkaskok [199]

Answer:

3.23

Step-by-step explanation:

6 0

2 years ago

Read 2 more answers

A sogun would most likely be found?

Archy [21]

Answer:

shogun would most likely be found. on the battlefield

8 0

2 years ago

For the figures below, assume they are made of semicircles, quarter circles and squares. For each shape, find the area and perim

ICE Princess25 [194]

Answer:

Part a) The area of the figure is $\frac{9}{2}(4+\pi )\ cm^{2}$

Part b) The perimeter of the figure is $3(2+2\sqrt{2}+ \pi)\ cm$

Step-by-step explanation:

Step 1

Find the area of the figure

In this problem we have that

The figure ABC is the half of a square and the other figure is a semicircle

Find the area of the figure ABC

we have

$AB=6\ cm, BC=6\ cm$

The area of the half square ABC is equal to find the area of triangle ABC

$A1=\frac{1}{2}*6*6=18\ cm^{2}$

Find the area of the semicircle

The area of the semicircle is equal to

$A2=\pi r^{2}/2$

we have that

$r=6/2=3\ cm$

substitute

$A2=\pi (3)^{2}/2$

$A2=(9/2) \pi\ cm^{2}$

The area of the figure is equal to

$18\ cm^{2}+(9/2) \pi\ cm^{2}= \frac{9}{2}(4+\pi )\ cm^{2}$

Step 2

Find the perimeter of the figure

The perimeter of the figure is equal to

$P=AB+AC+length\ CB$

we have

$AB=6\ cm$

Applying Pythagoras theorem

$AC=\sqrt{6^{2}+6^{2}}\\AC=6\sqrt{2}\ cm$

Remember that

the circumference of a semicircle is equal to

$C=\frac{1}{2}2\pi r=\pi r$

$r=6/2=3\ cm$

$C=\pi(3)$

$C=3 \pi\ cm$

The perimeter of the figure is equal to

$P=6\ cm+6\sqrt{2}\ cm+3 \pi\ cm$

Simplify

$P=3(2+2\sqrt{2}+ \pi)\ cm$

5 0

2 years ago

The solution set for 6a^2-a-5=0

Alex_Xolod [135]

Answer:

a=1 or a=5/6

Step-by-step explanation:

I'm going to attempt to factor 6a^2-a-5

a=6

b=-1

c=-5

Find two numbers that multiply to be a*c and add to be b.

a*c=-30 =-6(5)

b=-1 =-6+5

So replace -a with -6a+5a in the expression we started with

6a^2-6a+5a-5

now we factor by grouping

6a(a-1)+5(a-1)

(a-1)(6a-5)

Now let's solve the equation:

(a-1)(6a-5)=0

So a=1 or a=5/6

4 0

2 years ago