Part A: f(t) = t² + 6t - 20
  u = t² + 6t - 20
+ 20 + 20
u + 20 = t² + 6t
u + 20 + 9 = t² + 6t + 9
u + 29 = t² + 3t + 3t + 9
u + 29 = t(t) + t(3) + 3(t) + 3(3)
u + 29 = t(t + 3) + 3(t + 3)
u + 29 = (t + 3)(t + 3)
u + 29 = (t + 3)²
- 29 - 29
u = (t + 3)² - 29

Part B: The vertex is (-3, -29). The graph shows that it is a minimum because it shows that there is a positive sign before the x²-term, making the parabola open up and has a minimum vertex of (-3, -29).
------------------------------------------------------------------------------------------------------------------
Part A: g(t) = 48.8t + 28 h(t) = -16t² + 90t + 50
| t |   g(t) | | t | h(t) |
|-4|-167.2| | -4 | -566 |
|-3|-118.4| | -3 | -364 |
|-2| -69.6 | | -2 | -194 |
|-1| -20.8 | | -1 | -56 |
|0 |   -28 | | 0  |   50 |
|1 | 76.8 | |  1 | 124 |
|2 | 125.6| | 2 | 166 |
|3 | 174.4| | 3 | 176 |
|4 | 223.2| | 4 | 154 |
The two seconds that the solution of g(t) and h(t) is located is between -1 and 4 seconds because it shows that they have two solutions, making it between -1 and 4 seconds.

Part B: The solution from Part A means that you have to find two solutions in order to know where the solutions of the two functions are located at.

4 0

2 years ago

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An animal reserve has 20,000 elk. The population is increasing at a rate of 8% per year. This can be modeled by the function P(t

Scorpion4ik [409]

Answer:

The answer would be 31,737 elks.

Step-by-step explanation:

You would solve this by multiplying 1.08 by the power of 6 which equals 1.586874322944. You would then multiply this number by 20,000 which equals 31,737.4865 but since you can’t have .4865 of an elk the answer is just 31,737.

I hope this helps

8 0

2 years ago