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2 years ago

Write the prime factorization of 26.

Mathematics

2 answers:

katovenus [111]2 years ago

8 0

Answer:

The factors of 26 are 1,2,13,26 The prime factors of 26 are 2 and 13.

Step-by-step explanation:

aniked [119]2 years ago

8 0

Answer:

2 and 13

Step-by-step explanation:

First, we can see that the last digit of

is even, and thus

is divisible by

. If we divide by

, we find

. As

is a prime number, there are no further prime factors of

, and so the prime factorization of

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Someone please help. i will mark as brainliest if right :)

DIA [1.3K]

Answer:

The other factor is 5x-2

Step-by-step explanation:

Using the factorisation method:

Two numbers that multiply to give -10 and add to give +3:

+5 and -2

$5x^{2} +5x-2x-2$

$5x(x+1) -2(x+1)$

$(x+1)(5x-2)$

So the other factor is 5x-2

I'm not sure about the second part of the question but I hope you understood how to deal with the first part.

5 0

2 years ago

Can someone help me with this question: What is the 40th term of these sequences below. 13, 26, 39, 52,...... 6, 12, 18, 24,....

Nina [5.8K]

Answer:520; 240

Step-by-step explanation:

a. 13, 26, 39, 52,......

a = First term = 13

d = common difference = 26 - 13 = 13

40th term = a + (n - 1)d = a + (40-1)d = a + 39d

= 13 + (39 × 13)

= 13 + 507

= 520

b. 6, 12, 18, 24,.......

a = First term = 6

d = common difference = 12 - 6 = 6

40th term = a + 39d

= 6 + 39(6)

= 6 + 234.

= 240

8 0

2 years ago

Reasoning in a laboratory, the probability a bacterial colony thrives is 70%. The numbers 0 to 6 represent the outcome that a co

Maurinko [17]

Answer:

The probability that exactly half of the colonies will thrive = (1/3) = 0.3333

Step-by-step explanation:

The list of random numbers simulates the out comes of 4 colonies.

Based On the simulation in 6 trails, what is the probability that exactly half of the colonies will thrive?

The probability of an event is given mathematically as the number of elements in the event divided the total number of elements in the sample space.

Noting that the numbers 0 to 6 indicate that a colony thrives and the number 7 to 9 represent that a colony doesn't thrive.

The 6 trials are given as

4285; 3 colonies thrive, 1 doesn't.

6903; 3 colonies thrive, 1 doesn't.

3829; 2 colonies thrive, 2 don't.

7871; 1 colony thrives, 3 don't.

2868; 2 colonies thrive, 2 don't.

5137; 3 colonies thrive, 1 doesn't.

The number of trials where exactly 2 colonies thrive = 2

The total number of trials = 6

The probability that exactly half of the colonies will thrive = (2/6) = (1/3) = 0.3333

Hope this Helps!!!

3 0

2 years ago

Solve 600=6t show your work

Luba_88 [7]

600=6t

600/6=6t/6

600/6=t

100=t

5 0

2 years ago

Read 2 more answers

Given WXYZ is a rhombus.

Roman55 [17]

Answer:

Diagonal of rhombus bisect the angles of it.

Step-by-step explanation:

Given: WXYZ is a rhombus.

To prove: WY bisects Angle ZWX and Angle XYZ. ZX bisects Angle WZY and Angle YXW.

In rhombus WXYZ, WY is a diagonal.

In triangle WXY and triangle WZY,

$WX=WZ$ (sides of rhombus are equal)

$XY=ZY$ (sides of rhombus are equal)

$WY=WY$ (Common side)

By SSS postulate,

$\triangle WXY\cong \triangle WZY$

$\angle WYX\cong \angle WYZ$ (CPCTC)

$\angle XWY\cong \angle ZWY$ (CPCTC)

Hence prove, that WY bisects Angle ZWX and Angle XYZ.

Similarly,

In rhombus WXYZ, ZX is a diagonal.

In triangle WXZ and triangle YXZ,

$WX=YX$ (sides of rhombus are equal)

$XZ=XZ$ (Common side)

$WZ=YZ$ (sides of rhombus are equal)

By SSS postulate,

$\triangle WXZ\cong \triangle YXZ$

$\angle WZX\cong \angle YZX$ (CPCTC)

$\angle WXZ\cong \angle YXZ$ (CPCTC)

Hence prove, that ZX bisects Angle WZY and Angle YXW.

8 0

3 years ago

Write the prime factorization of 26.​

Write the prime factorization of 26.