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4 years ago

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The average home in the U.S. is expected to cost $240,000. A random sample of 65 homes sold this month showed an average price o

f $232,000. Assume that you have access to this data. We are interested in determining if the cost of the average home has decreased this month. If the test statistic is -1.79, what is the p-value

1 answer:

gulaghasi [49]4 years ago

8 0

Solution :

It is given that we have a null and an alternative hypothesis. The hypothesis are :

$H_0: \mu = 240,000$

$H_a : \mu < 240,000$

We have to find if the cost of average home has decreased or not in this month.

So it is given that the test statics is -1.79, so the p value associated with the test statics is less than ( α ) 0.01

Therefore, we can conclude that the cost of the average house is less than $ 240,000.

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PLSSS HELPPP A football quarterback goes for a two-point conversion when the ball is within 10 yards of the end zone. During the

Evgen [1.6K]

Answer:

The probability of missing both two-point conversion attempts is 7.5%

Step-by-step explanation:

We are informed that the probability of missing the first attempt is 50% of the time. Furthermore, the probability of missing on the second attempt given that he missed the first attempt is 15% of the time

Now,the probability of missing on both the two-point conversion attempts will simply be given by the product of these two probabilities since the events are independent;

50%*15% = 0.5 * 0.15 = 7.5%

Therefore, the probability of missing both two-point conversion attempts is 7.5%

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3 years ago

Find dy/dx x^2y=xy^2

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<span>x^2y=xy^2

Differentiate implicitly.

x^2y' + y(2x) = x(2yy') + y^2

x^2y' + 2xy = 2xyy' + y^2

x^2y' - 2xyy' = y^2 - 2xy

y'(x^2 - 2xy) = y^2 - 2xy

y' = (y^2 - 2xy)/(x^2 - 2xy)</span><span />

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3 years ago

41. Assuming that a man can complete the work alone in x days, his work in four days would be: a) b) X X C d) 4x x 42. If a man

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Percentage and ratio word problems require understanding of the relationship between variables from which the question is formed

The options that give the correct values of the duration of the work are;

$41. \ c) \ \dfrac{4}{x}$

$42. \ d) \ \dfrac{4}{x} + \dfrac{6}{y} = \dfrac{1}{5}$

43. a) 35 days

44. c) 21·a + 28·b = 1

45. c) (42, 56)

Reasons:

41. Number of days it takes a man to complete the work alone = x days

Therefore;

$The \ work \ done \ by \ the \ man \ in \ one \ day = \dfrac{1}{x}$

$The \ work \ done \ in \ four \ days \ by\ the \ man = 4 \times \dfrac{1}{x} = \dfrac{4}{x}$

The correct option is $c) \ \dfrac{4}{x}$

42. Number of days it takes a man to complete the work alone = x days

$Work \ done \ by \ a\ man \ in \ one \ day = \dfrac{1}{x}$

$Work \ done \ by \ four \ men \ in \ one \ day = \dfrac{4}{x}$

Number of days it takes a boy to complete the work alone = y days

$Work \ done \ by \ a \ boy \ in \ one \ day = \dfrac{1}{x}$

$Work \ done \ by \ six \ boys \ in \ one \ day = \dfrac{6}{y}$

4 men and 6 boys work for 5 days to complete the work

Therefore, work done by 4 men and 6 boys in 1 day is therefore;

$\dfrac{4}{x} + \dfrac{6}{y} = \dfrac{1}{5}$

The correct option is therefore;

$d) \ \dfrac{4}{x} + \dfrac{6}{y} = \dfrac{1}{5}$

43. As per the case study, we have;

Case 1

$\dfrac{4}{x} + \dfrac{6}{y} = \dfrac{1}{5}$

Which gives;

$\dfrac{6\cdot x + 4\cdot y}{y \cdot x} = \dfrac{1}{5}$

30·x + 20·y = y·x

Case 2

$\dfrac{3}{x} + \dfrac{4}{y} = \dfrac{1}{7}$

Which gives;

$\dfrac{4\cdot x + 3\cdot y}{y \cdot x} = \dfrac{1}{7}$

28·x + 21·y = y·x

Therefore;

30·x + 20·y = 28·x + 21·y

∴ 2·x = y

Plugging in the value of <em>y</em> = 2·x, in Case 1 gives;

$\dfrac{4}{x} + \dfrac{6}{2 \cdot x} = \dfrac{1}{5}$

$\dfrac{2 \times 4 + 6}{2 \times x} = \dfrac{14}{2 \times x} =\dfrac{7}{x} = \dfrac{1}{5}$

7 × 5 = x

x = 7 × 5 = 35

The number of days, <em>x</em>, it takes a man to complete the work alone, is given by option; a) <u>35 days</u>

44. For the equation $\dfrac{3}{x} + \dfrac{4}{y} = \dfrac{1}{7}$ , if $a = \dfrac{1}{x}$ , and $b = \dfrac{1}{y}$ , we have;

$3 \cdot a+ 4\cdot y = \dfrac{1}{7}$

21·a + 28·y = 1

The correct option is option C. <u>21·a + 28·b = 1</u>

45. A solution to the equation $\dfrac{3}{x} + \dfrac{4}{y} = \dfrac{1}{7}$ , is given by the values of <em>x</em>, and <em>y</em>, that gives;

$\dfrac{1}{14} + \dfrac{1}{14} = \dfrac{1}{7}$

We have;

3 × 14 = 42

4 × 14 = 56

Therefore, a solution to the equation is (42, 56)

The correct option is $c) \ \underline{ (42, \ 56)}$

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2 years ago

Find the value of 3x + 2 when 7+ x = 5

Sloan [31]

I hope this helps you

x= 5-7

x= -2

3.(-2)+2

-6+2

-4

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3 years ago

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Elza [17]

Answer:

1) 0.28

2) 0.35

Step-by-step explanation:

multiplication and subtraction

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3 years ago

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