We have to solve x in terms of a, b and c:
a x - 3 b = c
a x - 3 b + 3 b = c + 3 b
a x = c + 3 b
x = ( c + 3 b ) : a
Answer:
4 ) ( c + 3 b ) / a
Let the shortest side be x. Then the other two sides will be x+1 and x+2.
Perimeter = P = sum of the lengths of all three sides = x + (x+1) + (x+2)
This perimeter = 4x -1 (1 less than 4 times the shortest side).
Then x + x + 1 + x + 2 = 4x - 1
or: 3x + 3 = 4x -1 Subtr. 3x from both sides:
3 = x - 1
x=4, x+1=5, and x+2=6
The 3 sides have lengths 4, 5 and 6.
Alright,
(a) 2x+4(x-1)=2
2x+4x-4=2---- Distrubution of 4(x-1)
6x-4=2---- Combining like terms
6x=6---- Making -4 equal 0 by adding +4 to both sides
x=1---- Divide the coefficiant (6)
(b) 25-x=15-(3x+10)
25-x=15-3x-10----Distribute the -1
25-x=5-3x---- Combine like terms
25=5-2x---- Make -x equal 0 by adding +x to both sides
20=-2x---- Make 5 equal zero by subtracting 5 (or adding -5) to both sides
-10=x---- Divide by the coefficiant (-2)
(c) 4x= 2x+2x+5(x-x)
4x=2x+2x+5(0)---- Distribute. Alright this might look hard but realy it is 1x-1x so the answer is 0
4x=2x+2x---- 5 times 0 is 0
4x=4x---- Combine like terms
x=x ---- divide by the coefficiant
Alright! Hope this helps! ;)
I believe it’s the last answer. Rotation of 180 degrees clockwise with a dilation of 5.
Answer:
<h2>20 meters by 60 meters.</h2><h2>80 boards.</h2>
Step-by-step explanation:
We know that the ice rink is 1200 square meters, which means to enclose the rink we need dimensions of 20 meters by 60 meters, to have 1200 square meters of area.
Now, the boards are on the perimeter of the ice rink with dimensiosn 20 meters times 60 meters. So, its perimeter is
If each board is 2.0 meter long, that means we can divide to find the total number of boards we can have on the ice rink:
Therefore, with those dimensions, we can have 80 boards surrounding the ice rink.