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grandymaker [24]
3 years ago
6

Line m passes through points (1, 4) and (10, 9). Line n is parallel to line m. What is the slope

Mathematics
1 answer:
Assoli18 [71]3 years ago
3 0
We be back in school I don’t want
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Please help me out with this question.<br>much appreciation. Thanks.​
Alex_Xolod [135]

Answer:

there is nothing

Step-by-step explanation:

5 0
3 years ago
Kendra is flying a kite. The angle of elevation from Kendra to the kite is 56Á. If the distance from KendraÍs hands to the kite
Oliga [24]
<span>Assuming that the string of the kite does not sag. It then serves as the hypotenuse of the right triangle. The horizontal distance is the length of the base of the triangle. The horizontal distance can the be calculated using trigonometry: h = 50 cos(56 deg) = 28.0 ft.
</span>

I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!
3 0
3 years ago
If p = 4/5, what is the smallest value of n that satisfies the requirements for a normally distributed p?
adell [148]

Answer:

The smallest value of n that satisfies the requirements for a normally distributed p is 30

Step-by-step explanation:

The Central Limit Theorem says that if we have a random sample and the sample size is large enough (usually bigger than 30), then the sample proportion will follow a normal distribution with mean p, where p is the true population proportion.

8 0
3 years ago
Please please please help
Eduardwww [97]

Answer:

I. B. true

II. A true

Step-by-step explanation:

we can use the quadratic equation:

x=\frac{-b+-\sqrt{b^{2}-4*a*c}}{2*a}

we have:

1)x^{2} -4x+5

a=1 b=-4 c=5

x=\frac{-(-4)+-\sqrt{(-4)^{2}-4*1*5}}{2*1} \\\\x=\frac{4+-\sqrt{-4}}{2} \\\\x=\frac{4+-\sqrt{4} i}{2}\\\\x=\frac{4+-2i}{2} \\\\x_{1} =2-i\\\\x_{2} =2+i

the quadratic expression has two complex factors.

2)x^{2} -5x+14

a=1 b=-5 c=14

x=\frac{-(-5)+-\sqrt{(-5)^{2}-4*1*14}}{2*1} \\\\x=\frac{5+-\sqrt{-31}}{2} \\\\x=\frac{5+-\sqrt{31} i}{2}\\\\x_{1} =\frac{5-\sqrt{31}i }{2}\\ \\x_{2} =\frac{5+\sqrt{31}i }{2}

the solution of x^{2} -5x+14 are

x_{1} =\frac{5-\sqrt{31}i }{2}\\\\or\\x_{2} =\frac{5+\sqrt{31}i }{2}

3)2x^{2} -8x+5

a=2 b=-8 c=5

x=\frac{-(-8)+-\sqrt{(-8)^{2}-4*2*5}}{2*2} \\\\x=\frac{8+-\sqrt{24}}{4} \\\\x=\frac{8+-2\sqrt{6}}{4}\\\\x_{1} =2-\frac{\sqrt{6}}{2}\\ \\x_{2} =2+\frac{\sqrt{6}}{2}

7 0
3 years ago
Calculate the sizes of the unknown angles in each diagram.<br><br> Please, answer with explanation.
denis23 [38]

Step-by-step explanation:

a) 2z+3z+4z=180

9z=180

z=20

So,three angles are 40,60 and 80

b) (y+30)+(2y+80)+(y+10)=180

y+30+2y+80+y+10=180

4y+120=180

4y=60

y=15

Three angles are 45,110,25

5 0
3 years ago
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