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Alex777 [14]
3 years ago
12

Are angles 1 and angle 4 vertical? Are angles 3 and angle 5 vertical?

Mathematics
2 answers:
ser-zykov [4K]3 years ago
6 0
None are vertical, they have to be straight
tamaranim1 [39]3 years ago
3 0

Answer:

All of them are not vertical angles.

Step-by-step explanation:

Because they are not directly vertical from each other.

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Find all the powers of 3 that are in the range 3 through 1000
Ksivusya [100]
So just use a calculator but here goes
3^1=3
3^2=9
3^3=27
3^4=81
3^5=243
3^6=729

and 3^7 is 2187 which is excluded











8 0
3 years ago
Let the graph of g be a vertical stretch by a factor of 2 followed by a translation 3 units down of the graph of f(x) = x2 Write
Mrrafil [7]

Answer:

g(x)= x2

Step-by-step explanation:

g(x)=x2 = f(x)=x2

5 0
3 years ago
What is the vertex of the graph of the function f(x) = x2 − 4x?
Vsevolod [243]

Answer:

(2, -4).

Step-by-step explanation:

x^2 - 4x

= (x - 2)^2 - 4.

So the vertex is at

(2, -4).

6 0
3 years ago
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Two times antonio's age plus three times sarah's age equals 34. Sarah's age is also 5 times antonio's age. how old is sarah
Sidana [21]
Sarah's 10 years old.
Antonio's 2 years old.

2 x 2 = 4
10 x 3 = 30
4 + 30 = 34

2 x 5 = 10
4 0
4 years ago
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If 3x-y=123x−y=123, x, minus, y, equals, 12, what is the value of \dfrac{8^x}{2^y} 2 y 8 x ​ start fraction, 8, start superscrip
julia-pushkina [17]

Answer:

2^{12}=4,096

Step-by-step explanation:

You know that 3x-y=12 and have to find

\dfrac{8^x}{2^y}

Use the main properties of exponents:

1. (a^m)^n=a^{m\cdot n}

2. \dfrac{a^m}{a^n}=a^{m-n}

Note that

8=2^3,

then

7^x=(2^3)^x=2^{3\cdot x}=2^{3x}

Now

\dfrac{8^x}{2^y}=\dfrac{2^{3x}}{2^y}=2^{3x-y}

Since 3x-y=12, then 2^{3x-y}=2^{12}=4,096

3 0
3 years ago
Read 2 more answers
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