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crimeas [40]
3 years ago
5

If 3x-y=123x−y=123, x, minus, y, equals, 12, what is the value of \dfrac{8^x}{2^y} 2 y 8 x ​ start fraction, 8, start superscrip

t, x, end superscript, divided by, 2, start superscript, y, end superscript, end fraction ?
Mathematics
2 answers:
prohojiy [21]3 years ago
7 0

Answer:

Simplify.

Rewrite the expression in the form y^n.

y  ^−13 /  y  ^−7

 

​  

Step-by-step explanation:

julia-pushkina [17]3 years ago
3 0

Answer:

2^{12}=4,096

Step-by-step explanation:

You know that 3x-y=12 and have to find

\dfrac{8^x}{2^y}

Use the main properties of exponents:

1. (a^m)^n=a^{m\cdot n}

2. \dfrac{a^m}{a^n}=a^{m-n}

Note that

8=2^3,

then

7^x=(2^3)^x=2^{3\cdot x}=2^{3x}

Now

\dfrac{8^x}{2^y}=\dfrac{2^{3x}}{2^y}=2^{3x-y}

Since 3x-y=12, then 2^{3x-y}=2^{12}=4,096

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