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givi [52]
3 years ago
12

What is the vertex of the graph of the function f(x) = x2 − 4x?

Mathematics
2 answers:
Vsevolod [243]3 years ago
6 0

Answer:

(2, -4).

Step-by-step explanation:

x^2 - 4x

= (x - 2)^2 - 4.

So the vertex is at

(2, -4).

ExtremeBDS [4]3 years ago
6 0

Answer:

(2,-4)

Step-by-step explanation:

x²-4x

First, we need to complete the square of this quadratic.

1) Half the coefficient of x and subtract it (depends on the sign) from x. Then, square the whole expression.

(x-2)²

2) If this was to be expanded as a double bracket, we would acquire:

x²-4x+4

In order to achieve the form above, we need to subtract 4. This can be found quickly by subtracting the square of the integer from the bracket. (Ignore the sign when squaring here.)

(x-2)²<u>-4</u>           ------>This is in the completing the square from.

From this, the vertex is determined by using the opposite sign of the number in the bracket for the x coordinate and the outside number is kept constant for the y. Note that, in graph transformations, the number inside the brackets is the "opposite of what you expect"; the same logic is applied here.

Therefore, the vertex is (2,<u>-4</u>)

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The extensions of the legs AB and CD of a trapezoid ABCD intersect at point E. Find the lengths of the sides of △AED if AB=5cm,
Lynna [10]

Answer:

  AE = 15 cm; ED = 18 cm; AD = 15 cm (given)

Step-by-step explanation:

ΔBEC ~ ΔAED so ...

   AD/BC = AE/BE = (BE+AB)/BE = 1 + AB/BE

Substituting given numbers (lengths in centimeters), we have ...

  15/10 = 1 + 5/BE

  1/2 = 5/BE

  BE = 10

Similarly, ...

  1/2 = 6/CE

  CE = 12

Then the unknown sides are ...

  AE = AB + BE = 5 + 10 = 15 . . . cm

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8 0
3 years ago
Which of the following expressions is equivalent to a3 + b3?
lubasha [3.4K]
ANSWER
{a}^{3}  + {b}^{3} = (a + b)( {a}^{2 }  - ab +  {b}^{2} )


EXPLANATION

To find the expression that is equivalent to
{a}^{3}  + {b}^{3}
we must first expand
{(a + b)}^{3}
Then we rearrange to find the required expression.


So let's get started.


{(a + b)}^{3}  = (a + b) {(a + b)}^{2}

We expand the parenthesis on the right hand side to get,



{(a + b)}^{3}  = (a + b) ( {a}^{2} + 2ab +  {b}^{2}  )



We expand again to obtain,

{(a + b)}^{3}  =  {a}^{3}  + 3 {a}^{2}b + 3a {b}^{2}   +  {b}^{3}


Let us group the cubed terms on the right hand side to get,

{(a + b)}^{3}  =  {a}^{3}   +  {b}^{3}  + 3 {a}^{2}b + 3a {b}^{2}




{(a + b)}^{3}  =  {a}^{3}   +  {b}^{3}  + 3ab (a+ b)





We make the cubed terms the subject,

{(a + b)}^{3}  - 3ab (a+ b) =  {a}^{3}   +  {b}^{3}

We factor to get,


(a + b)({(a + b)}^{2}  - 3ab ) =  {a}^{3}   +  {b}^{3}


We expand the bracket on the left hand side to get,

(a + b)( {a}^{2}  + 2ab +  {b}^{2}   - 3ab ) =  {a}^{3}   +  {b}^{3}


We finally simplify to get,

(a + b)( {a}^{2}   - ab +  {b}^{2}  ) =  {a}^{3}   +  {b}^{3}
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