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KiRa [710]
3 years ago
13

A student pipets exactly 5.00ml of 3.47 x 10.2M FeCl3 solution into a Vol flask and adds enough water to it to make 250ml of sol

ution. What is the concentration of the diluted solution?
Chemistry
1 answer:
andrew-mc [135]3 years ago
5 0

Answer:

The concentration would be 0.76 mol/L.

The most common way to solve this problem is to use the formula

c1V1=c2V2

In your problem,

c1 = 4.2 mol/L; V1 = 45.0 mL

c2 = ?; V2 = 250 mL

c2=c1×V1V2 = 4.2 mol/L × 45.0mL250mL = 0.76 mol/L

This makes sense. You are increasing the volume by a factor of about 6, so the concentration should be about ¹/₆ of the original (¹/₆ × 4.2 = 0.7).

Explanation:

if it is helpful...... plzz like and follow

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Part A A compass contains a magnet. The magnet responds to Earth's magnetic field. The magnet's north pole points north from mos
valentina_108 [34]

Answer:

The Earth's magnetic field intensity is roughly between 25,000 - 65,000 north magnetic pole is 86.50°N and 164.04°E and the south magnetic pole is 64.07°S and 135.88°E

7 0
3 years ago
1: At which temperature would a reaction withΔH = -102 kJ/mol, ΔS = -0.188 kJ/(mol×K) be spontaneous? 2: At which temperature wo
Naddik [55]

Answer:

1: At temperatures below 542.55 K

2: At temperatures above 660 K

Explanation:

Hello there!

In this case, according to the thermodynamic definition of the Gibbs free energy, it is possible to write the following expression:

\Delta G=\Delta H-T\Delta S

Whereas ΔG=0 for the spontaneous transition. In such a way, we proceed as follows:

1:

0=\Delta H-T\Delta S\\\\T=\frac{-102kJ/mol}{-0.188kJ/mol-K} \\\\T=542.55K

It means that at temperatures lower than 542.55 K the reaction will be spontaneous.

2:

0=\Delta H-T\Delta S\\\\T=\frac{132kJ/mol}{0.200kJ/mol-K} \\\\T=660K

It means that at temperatures higher than 660 K the reaction will be spontaneous.

Best regards!

7 0
3 years ago
What is the correct name for the cyclic alkane shown on the right?
Soloha48 [4]

Answer: C

Explanation:

4 0
3 years ago
Read 2 more answers
Calcium oxide or quicklime (CaO) is used in steelmaking, cement manufacture, and pollution control. It is prepared by the therma
Elena-2011 [213]

Answer:

The yearly release of CO_2 into the atmosphere is 6.73\times 10^{10} kg.

Explanation:

CaCO_3(s)\rightarrow CaO(s) + CO_2(g)

Annual production of CaO = 8.6\times 10^{10} kg=8.6\times 10^{13} g

Moles of CaO :

\frac{8.6\times 10^{13} g}{56 g/mol}=1.53\times 10^{12} moles

According to reaction, 1 mole of CaO is produced along with 1 mole of carbon-dioxide.

Then along with  1.53\times 10^{12} moles of CaO moles of carbon-dioxide moles produced will be:

\frac{1}{1}\times 1.53\times 10^{12} moles=1.53\times 10^{12} moles of carbon-dioxide

Mass of 1.53\times 10^{12} moles of carbon-dioxide:

1.53\times 10^{12}mol\times 44 g/mol=6.73\times 10^{13} g =6.73\times 10^{10} kg

The yearly release of CO_2 into the atmosphere is 6.73\times 10^{10} kg.

6 0
3 years ago
The longer the bond, the smaller the bond enthalpy. the longer the bond, the smaller the bond enthalpy. false true
Temka [501]

True

As the shorter the bond, the stronger it is hence more energy will be required to overcome this bond

5 0
3 years ago
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