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Archy [21]
3 years ago
7

Iodine-131 has a half-life of 8 days. How long would it take for the number of unstable nuclei in the sample to be reduced from

1,000 to 125?
Chemistry
1 answer:
Svet_ta [14]3 years ago
7 0

Answer:

After one-half life: 16 mg

After 2-half lives: 8 mg

After 3-half lives: 4 mg

After 4-half lives: 2 mg

After 5-half lives: 1 mg

(5 half-lives) x (8 days/half-life) = 40 days  

or doing it the mathematical way:  Let z be the number of days to be found:

1 mg = 32 mg x (1/2)^(z / 8 days)  

1/32 = (1/2)^(z / 8 days)  

log (1/32) = (z / 8 days) x log (1/2)  

z / 8 days = log (1/32) / log (1/2)

z = 8 days x log (1/32) / log (1/2) = 40 days

Explanation:

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borishaifa [10]

Answer:

Explanation:

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Here HBr is an acid but Sn is not a base . It is a metal . So it is not an acid - base reaction .

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3 years ago
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Explanation:

3!!!!!

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3 years ago
Does adding coefficients to a chemical equation disobey the law of definite proportions? Explain your answer.
Temka [501]

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Example :             2 Mg + O2 → 2 MgO              

In the balanced equation above, 2 moles of Mg reacts with 1 mole of O2 to produce 2 moles of MgO.

mass of 2 moles of Mg  = 24×2= 48 grams

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total mass of products = 80 grams

It is clear that the number of grams of matter before and after the reaction is the same and  equals to 80 grams, so obeys the law of definite proportions..


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