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valentinak56 [21]
3 years ago
6

8. What is the name of this compound?

Chemistry
1 answer:
olga2289 [7]3 years ago
6 0

Answer:

tert-butyl bromide

Explanation:

sec-butyl bromide

CH3 -CH-CH2-CH3

         Br

tert-butyl bromide

       CH3

CH3-C- Br

       CH3

isopropyl bromide

       CH3

CH3-CH-Br

isobutyl bromide

       CH3

CH3-CH-CH2-Br

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In a 10-gram sample of carbon and a 10-gram sample of sulfur, how many more moles of carbon are there than sulfur?
8_murik_8 [283]
Your answer will be the second option

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Which of the following wouldn't be a good tool to use when measuring pH values of solutions?
aev [14]

litmus paper

Because it will just tell if the solution is acidic or basic, it won't tell the pH

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3 years ago
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Select the pair that has the larger atom or ion listed first.
Sedbober [7]

Answer:

Correc option: Br^- \, , Kr

Explanation:

size of atom : it says somthing about how many shell present in a particular atom or ion and it can also be evaluated on the basis of radius of atom.

Br^- and Kr has highest number of shell as compared to other group of species .

Na ,S , Mg ,P all are from 3rd period but Kr and Br^- in the 4th period so size of species of this group will more,

Size increases on increasring the shell number

3 0
3 years ago
What is the pH of a 0.640 M solution of C₅H₅NHBr (Kb of C₅H₅N is 1.7 × 10⁻⁹)?
Elden [556K]

The pH of a 0.64 M solution of pyridine (C₅H₅N) is 9.52.  

<h3>What is pH ?</h3>

A figure expressing the acidity or alkalinity of a solution on a logarithmic scale on which 7 is neutral, lower values are more acid and higher values more alkaline.

The equation for the protonation of the base pyridine is the following:

C₅H₅N + H₂O ⇄ C₅H₅NH⁺ + OH⁻   (1)

Kb = 1.7 × 10⁻⁹ (Given)

To calculate the pH of the solution we need to use the following equation:

pH + pOH = 14

<em>pH = 14 - pOH</em>

     =14 - [-log[OH⁻]]

    = 14 + log[OH⁻]

Now, we need to find the concentration of the OH⁻ ions. Since pyridine is a weak base, at the equilibrium we have (eq 1):

C₅H₅N  +  H₂O  ⇄  C₅H₅NH⁺  +  OH⁻

0.64 - x                          x              x

After entering the values of [C₅H₅N] = 0.64-x, [C₅H₅NH⁺] = x, and [OH⁻] = x, into equation (2) we can find the concentration of OH⁻:

1.7 × 10⁻⁹  =[C₅H₅NH⁺]  [OH⁻]  /  [C₅H₅N]

                = x . x / 0.64-x

1.7 × 10⁻⁹ (0.64-x) - x² = 0

Solving the above quadratic equation for x, we have :

  • x₁ = -3.32 x 10⁻⁵
  • x₂ = 3.32 x 10⁻⁵

Now, We can calculate the pH, after taking the positive value, x₂, (concentrations cannot be negative) and entering into above equation :

<em />

<em>pH = </em>14 + log[OH⁻]

     = 14 + log (3.32 x 10⁻⁵)

 

     = 9.52

Therefore, the pH of the solution of pyridine is 9.52.

Find more about pH here:

brainly.com/question/8834103?referrer=searchResults

#SPJ1

3 0
2 years ago
Thinner in the center that at the edges; virtual image smaller.
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<h3><u>Answer</u>;</h3>

Concave Lenses

<h3><u>Explanation</u>;</h3>
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