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3 years ago

PLEASE DONT BAN ME AND ERASED MY ACCOUNT AGAIN BRAINLY!

Mathematics

2 answers:

leva [86]3 years ago

6 0

Answer:

question 11 = (x + 4)^2

question 12 = 3x(x+1)^2

Step-by-step explanation:

question 11

x^2+8x+16

x^2 + 4x + 4x + 16

x(x+4) + 4(x+4)

(x+4)(x+4)

(x+4)^2

question 12

3x^3 + 6x^2 + 3x

3x(x^2 + 2x + 1)

3x(x^2 + x + x + 1)

3x(x^2 + 1x + x +1)

3x(x(x+1) + x +1)

3x(x(x+1) +1 (x+1))

3x(x+1)(x+1)

3x(x+1)^2

torisob [31]3 years ago

3 0

Answer:

for question 11: I am guessing C. for question 12: I am guessing B. I am sorry if I am wrong but I hope that I helped u

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timurjin [86]

Amount of oil sandi has = 2 1/3 * 12

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3 years ago

I need help, -3x+9+4x=10 just wondering if the answer is X=1

enyata [817]

Answer:

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2 years ago

Read 2 more answers

Of the 12 temporary employees in a certain company, 4 will be hired as permanent employees. If 5 of the 12 temporary employees a

Ivenika [448]

Answer:

<h2>70 possible groups</h2>

Step-by-step explanation:

Given the total number of employee to be equal to 12 temporary employee.

Number of women employee = 5 women

Number of men employee = 12 - 5 = 7 men

If 4 will be hired as permanent employees, the possible ways they can be grouped so that the 4 temporary employees consists of 3 women and 1 man can be done by applying the combination formula.

Combination has to do with selection. For example, if r objects are to be selected from n pool of similar objects, this can be done in <em>nCr </em>different ways.

$nCr = \frac{n!}{(n-r)!r!}$

According to question, we are to select 3 women from 5 women and 1 man from 7 men. Based on similarity in sex, this can be done in (5C3* 7C1) different ways .

$5C3 * 7C1\\= \frac{5!}{(5-3)!3!} * \frac{7!}{(7-1)!1!}\\\\= \frac{5!}{2!3!} * \frac{7!}{6!1!}\\\\= \frac{5*4*3!}{3!*2} * \frac{7*6!}{6!*1}\\\\= \frac{20}{2} * \frac{7}{1}\\ \\= 10*7\\\\= 70\ possible\ groups$