200/5 = 40 miles per inch. 40x7=280 actual miles.
Let
x--------> the border’s length
y--------> the border’s width
P--------> perimeter of the border
we know that
x=5+y------> equation 1
P=2*[x+y]-----> P=2x+2y
P <=180 ft
(2x+2y) <= 180-------> equation 2
substitute the equation 1 in equation 2
2*[5+y]+2y <= 180
10+2y+2y <= 180
4y <= 180-10
4y <=170
y <=42.5 ft
so
the maximum value of the width is 42.5 ft
for y=42.5 ft
x=42.5+5------> x=47.5 ft
the answer is
the width of the border is less than or equal to 42.5 ft
A. 314 sq cm
Explanation: pi•r^2
3.14 x 10^2
3.14 x 100 =314
Answer:
7:11
Step-by-step explanation:
You place the numbers in the order given.
70:110
Then reduce it to the lowest term. In this case by 10.
70 ÷10=7
110÷10=11Therefore, the answe is
7:11
