3 years ago

Https://brainly.com/question/22438984 //help ASAP PLEASE

Mathematics

2 answers:

vesna_86 [32]3 years ago

8 0

Answer:

theres nothing there

Step-by-step explanation:

gayaneshka [121]3 years ago

8 0

Answer:

yeah brainly is one of the best learning app for students

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If the mean weight of 4 backfield members on the football team is 221 lb and the mean weight of the 7 other players is 202 lb, w

MatroZZZ [7]

Let $x_1, x_2, x_3, x_4, x_5, x_6, x_7, x_8, x_9, x_{10}, x_{11}$ be the weight of i-th player.

1. If the mean weight of 4 backfield members on the football team is 221 lb, then

$\dfrac{x_1+x_2+x_3+x_4}{4}=221\ lb.$

2. If the mean weight of the 7 other players is 202 lb, then

$\dfrac{x_5+x_6+x_7+x_8+x_9+x_{10}+x_{11}}{7}=202\ lb.$

3. From the previous statements you have that

$x_1+x_2+x_3+x_4=221\cdot 4=884 \lb,\\ \\x_5+x_6+x_7+x_8+x_9+x_{10}+x_{11}=202\cdot 7=1414\ lb.$

Add these two equalities and then divide by 11:

$x_1+x_2+x_3+x_4+x_5+x_6+x_7+x_8+x_9+x_{10}+x_{11}=884+1414=2298\ lb,\\ \\\dfrac{x_1+x_2+x_3+x_4+x_5+x_6+x_7+x_8+x_9+x_{10}+x_{11}}{11}=\dfrac{2298}{11}=208\dfrac{10}{11}\ lb.$

Answer: the mean weight of the 11-person team is $208\dfrac{10}{11}\ lb.$

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2 years ago

The number 3 help now please

PSYCHO15rus [73]

-6, all of them are the absolute value of 6 or just 6, -6 isn't equivalent to 6.

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3 years ago

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sukhopar [10]

Answer:

(a) 1km

(b)80 fence panels

Step-by-step explanation:

(a) perimeter = 300+300= 600

200+200= + 400

=1000m

1km = 1000m

(b).

1panel = 2.5 m 1× 200÷2.5 = 80

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