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Sholpan [36]
3 years ago
11

Help!!! I'm not really good at graphs so I also need an explanation please!​

Mathematics
1 answer:
Gnom [1K]3 years ago
6 0

Answer:

Hi, I think it's DEGF

Step-by-step explanation:

for y=x-2,

just move y=x down 2 units.

for x=-2,

it's the easiest one, just see if there is a vertical crossing -2 on the x-axis.

for-2x+4,

you can see it as move y=-2x up 4 units, and for y=-2x, you can find it out by sub (1,-2) and (0,0) onto the graph.

for x²-4,

see it as y=x² moved down 4 units. for y=x², it's simply a parabola which is symmetrical along y-axis and crossing (0,0). And remember that since the coefficient of x² is positive, the graph is open upward.

Hope this will help u!!

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Advandia is a drug used to treat diabetes, but it may cause an increase in heart attacks among a population already susceptible.
sergiy2304 [10]

Answer:

a) The proportions are not form matched-pairs data.

b) The null hypothesis failed to be rejected.

There is  not enough evidence to support the claim that there is evidence of a significant increase in the proportion of people who suffer heart attacks when using Avandia compared to other treatments.

Step-by-step explanation:

a) Two data sets are "paired" when the following one-to-one relationship exists between values in the two data sets:

  • Each data set has the same number of data points.
  • Each data point in one data set is related to one, and only one, data point in the other data set.

None of this conditions apply in this case, so the proportions are not form matched-pairs data.

b) This is a hypothesis test for the difference between proportions.

The claim is that there is evidence to suggest that there is a significant increase in the proportion of people who suffer heart attacks when using Avandia compared to other treatments.

Then, the null and alternative hypothesis are:

H_0: \pi_1-\pi_2=0\\\\H_a:\pi_1-\pi_2> 0

The significance level is 0.05.

The sample 1 (Avindia treatment), of size n1=1456 has a proportion of p1=0.0185.

p_1=X_1/n_1=27/1456=0.0185

The sample 2 (other treatment), of size n2=2895 has a proportion of p2=0.0142.

p_2=X_2/n_2=41/2895=0.0142

The difference between proportions is (p1-p2)=0.0044.

p_d=p_1-p_2=0.0185-0.0142=0.0044

The pooled proportion, needed to calculate the standard error, is:

p=\dfrac{X_1+X_2}{n_1+n_2}=\dfrac{27+41}{1456+2895}=\dfrac{68}{4351}=0.0156

The estimated standard error of the difference between means is computed using the formula:

s_{p1-p2}=\sqrt{\dfrac{p(1-p)}{n_1}+\dfrac{p(1-p)}{n_2}}=\sqrt{\dfrac{0.0156*0.9844}{1456}+\dfrac{0.0156*0.9844}{2895}}\\\\\\s_{p1-p2}=\sqrt{0.00001+0.00001}=\sqrt{0.00002}=0.004

Then, we can calculate the z-statistic as:

z=\dfrac{p_d-(\pi_1-\pi_2)}{s_{p1-p2}}=\dfrac{0.0044-0}{0.004}=\dfrac{0.0044}{0.004}=1.1

 

This test is a right-tailed test, so the P-value for this test is calculated as (using a z-table):

P-value=P(z>1.1)=0.1358

As the P-value (0.1358) is bigger than the significance level (0.05), the effect is not significant.

The null hypothesis failed to be rejected.

There is  not enough evidence to support the claim that there is evidence to suggest that there is a significant increase in the proportion of people who suffer heart attacks when using Avandia compared to other treatments.

8 0
4 years ago
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Please help! I give BRAINLIEST for the first out of two who answer!!
astra-53 [7]

I'm pretty sure like 80% sure its R'P'Q' if not I'm very sorry

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4 years ago
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I really need help with trigonometry and laws of sine I’m being timed so please help me
natima [27]

Answer:

square root of 75, using Pythagorean theorem.

Step-by-step explanation:

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liraira [26]

Answer:

It can help us bc X is origanlly factored but when solving forX you do need to un factor to get it into simplest form

Step-by-step explanation:

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3 years ago
6.<br>What is the value of​
trapecia [35]

Answer:

\large\boxed{\dfrac{1}{27}}

Step-by-step explanation:

\dfrac{\left(\frac{1}{3}\right)^2\cdot\left(\frac{1}{3}\right)^{-7}}{\left[\left(\frac{1}{3}\right)^4\right]^{-2}}\\\\\text{use}\\\\a^n\cdot a^m=a^{n+m}\\\\\dfrac{a^n}{a^m}=a^{n-m}\\\\(a^n)^m=a^{nm}\\\\=\dfrac{\left(\frac{1}{3}\right)^{2+(-7)}}{\left(\frac{1}{3}\right)^{(4)(-2)}}=\dfrac{\left(\frac{1}{3}\right)^{-5}}{\left(\frac{1}{3}\right)^{-8}}=\left(\dfrac{1}{3}\right)^{-5-(-8)}\\\\=\left(\dfrac{1}{3}\right)^{-5+8}=\left(\dfrac{1}{3}\right)^3=\dfrac{1^3}{3^3}=\dfrac{1}{27}

8 0
3 years ago
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