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Vlad1618 [11]
2 years ago
7

The first digit of a string of 2002 digits is a 1. Any two-digit number formed by consecutive digits within this string is divis

ible by 19 or 31. What is the largest possible last digit in this string
Mathematics
1 answer:
Umnica [9.8K]2 years ago
4 0

The largest possible last digit in the string of 2002 digits and number divisible by 19 or 31 is 9.

Given the first digit of a string of 2002 digits is 1 and the two digit number formed by consecutive digits within the string is divisible by 19 or 31.

We have to tell the last largest digit of such number.

Two digit numbers divisible by 19=19,38,57,76,95.

Two digit numbers divisible by 31=31,62,93,124

Number started with 1 =19

Last digit is 9

We have said that the number should be divisible by 19 or 31 not from both and started with 1.

Hence the largest possible last digit and number divisible by 19 or 31 in this string is 9.

Learn more about digits at brainly.com/question/26856218

#SPJ4

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Find the length of CD shown in red below. Show all work.
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By definition of circumference, the length of the arc EF (radius: 6 in, central angle: 308°) shown in red is approximately equal to 32.254 inches.

<h3>How to calculate the length of an arc</h3>

The figure presents a circle, the arc of a circle (s), in inches, is equal to the product of the <em>central</em> angle (θ), in radians, and the radius (r), in inches. Please notice that a complete circle has a central angle of 360°.

If we know that θ = 52π/180 and r = 6 inches, then the length of the arc CD is:

s = [(360π/180) - (52π/180)] · (6 in)

s ≈ 32.254 in

By definition of circumference, the length of the arc EF (radius: 6 in, central angle: 308°) shown in red is approximately equal to 32.254 inches.

<h3>Remark</h3>

The statement has typing mistakes, correct form is shown below:

<em>Find the length of the arc EF shown in red below. Show all the work.</em>

To learn more on arcs: brainly.com/question/16765779

#SPJ1

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