Answer:
5 hours
Step-by-step explanation:
Time taken for trip : t + 1
Time taken for return : t
Avg. speed (trip) : 256 km/h
Avg. speed (return) : 320 km/h
The distances covered on both trips are equal.
⇒ Distance (trip) = Distance (return)
⇒ Speed (trip) × time (trip) = Speed (return) × time (return)
⇒ (256)(t + 1) = (320)(t)
⇒ 256t + 256 = 320t
⇒ 64t = 256
⇒ t = 4 hours
<u>Time (trip)</u> = t + 1 = 4 + 1 = 5 hours
<h3>
Answer: 20% increase</h3>
======================================================
Explanation:
A = old value = 110
B = new value = 132
C = percent change
C = 100*(B-A)/A
C = 100*(132-110)/110
C = 20%
The positive C value means we have a percent increase, which corresponds to the fact that A = 110 increases to B = 132.
The B-A = 132-110 = 22 portion up top indicates that the increase is 22 pounds, which when divided over 110, gets us 22/110 = 0.20 = 20%
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Checking the answer:
20% of 110 = 0.20*110 = 22
She's able to lift 22 extra pounds on top of the 110 pounds she can handle previously, so she can now lift 110+22 = 132 pounds. The answer is confirmed.
Answer:
See below
Step-by-step explanation:
I believe that you only had to do letters F, H, and J. In that case, let's go over each one!
F: For isolating
, we need to get rid of the 1/2 first. Let's multiply each side by 2:

After this, we just subtract
from each side to get
. Dark Blue is correct! Let's now plug in those numbers below:

G: Let's isolate the vw^2 on one side by subtracting y from each side:

Let's now divide each side by v, then put each side under a square root to get our final answer:

Orange is correct! Again, let's solve the problem underneath:
w=
H: This one has some stuff that we haven't worked with quite yet (like terms), but our approach is the same: isolate c on one side of the equation.

Purple is correct! Let's solve the problem:

1 Expand
1.4t-0.4t+1.24=5.8
2 Simplify 1.4t-0.4t+1.241.4t−0.4t+1.24 to t+1.24t+1.24
t+1.24=5.8
3 Subtract 1.241.24 from both sides
t=5.8−1.24
4 Simplify 5.8-1.245.8−1.24 to 4.564.56
t=4.56