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puteri [66]
3 years ago
15

Find the midpoint of the segment with the given endpoints. (-7,- 9) and (-2,7)

Mathematics
1 answer:
Zina [86]3 years ago
4 0

Answer:

I think the answer is go die and pls don’t forget to like this post

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Please hawlp pls.......
Amiraneli [1.4K]

Answer:

(a) A(x)=160x-2x^{2}

(b) x=40\textrm{ m}

(c) Maximum area=3200 square meters

Step-by-step explanation:

(a)

Given:

Total length for fencing = 160 m

Width of the rectangle = x m.

Let the other length of the rectangle be y m.

Then, from the figure,

x+y+x=160\\2x+y=160\\y=160-2x

Now, area of a rectangle is equal to the product of its length and width.

So, area is, A(x)=xy=x(160-2x)=160x-2x^{2}

(b)

Given:

A(x)=160x-2x^{2}

For maximum area, derivative of area with respect to x must be 0.

So, \frac{dA}{dx}=0\\\frac{d}{dx}(160x-2x^{2})=0\\160-4x=0\\4x=160\\x=\frac{160}{4}=40\textrm{ m}

Therefore, for maximum area, x=40\textrm{ m}.

(c)

Given:

A(x)=160x-2x^{2}

Maximum area occurs at x=40. Plug in 40 for x in A(x) expression. This gives,

Maximum area is,

A(x=40)=160(40)-2(40)^{2}\\A(x=40)=6400-2\times 1600\\A(x=40)=6400-3200=3200\textrm{ }m^{2}

Therefore, maximum area is 3200 square meters.

3 0
4 years ago
What property is X=X?
masha68 [24]
Reflexive property

for all real numbers (x)
a number equals itself (x=x)
5 0
3 years ago
What are the phase shift and period for the function y 3cos[4(0 + 459)]-4?
RUDIKE [14]
I dont know the answer

3 0
3 years ago
The two-way table shows the number of students in a school who have bikes and/or skateboards at home:
Tpy6a [65]
If you are looking at the total of just people who have just bikes that's 40 and people who have just skateboards that's 10 so 30 but if its the total of bikes that's 72 and the total of skateboards that's 42 which is also 30. My best guess seeing as i don't know what math class you are in is 30.
3 0
4 years ago
Hector invests $800 in an account that earns 6.98% annual interest compounded semiannually. Rebecca invests $1000 in an account
Roman55 [17]
A=P (1+r/n)^nt

A= Total amount invested, P=principal amount, r=Interest rate, n=number of time in a year when the interest is earned (for annual, n=1; for semi-annual, n=2, ...), t = time in years

In the current scenario, case 1, n=2; case 2, n=1 and A1=A2, t1=t2
Therefore,
800(1+0.0698/2)^2t = 1000(1+0.0543/1)t
Dividing by 800 on both sides;
(1+0.0349)^2t = 1.25(1+0.02715)^t
(1.0349)^2t = 1.25(1.02715)^t
Taking ln on both sides of the above equation;
2t*ln (1.0349)= ln 1.25 + t*ln (1.02715)
2t*0.0343 = 0.2231+ t*0.0268
0.0686 t = 0.2231+0.0268 t
(0.0686-0.0268)t = 0.2231
0.0418t=0.2231

t=5.337 years

Therefore, after 5.337 years or 5 years and approximately 4 months, their value of investments will be equal.

This value will be,
A=800(1+0.0698/2)^2*5.337 = $1,153.76
3 0
4 years ago
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