Answer:
7
Step-by-step explanation:
g(x) = 3/2 x + 4
g(2) = 3/2 * 2 + 4
g(2) = 3 +4
g(2) = 7
Answer:
You need more data
Step-by-step explanation:
Answer:
1. 6
2. 23
Step-by-step explanation:
1.
logx+1 ( x^2 + 2x + 1)^3
= 3logx+1 ( x^2 + 2x + 1)
= 3 logx+1 (x + 1)^2
= 6 logx+1 (x + 1) Now the logx+1 x+1 = 1 so
The answer is 6.
2.
log11 11^23
= 23 log11 11
As in question 1 log11 11 = 1
So the answer is 23.
Answer:
Step-by-step explanation:
For this case we are interested on the region shaded on the figure attached.
And we can find the volume with the method of rings.
The area on this case is given by:
![A(x) = \pi [f(x)]^2 = \pi r^2 = \pi [3x]^2 = 9\pi x^2](https://tex.z-dn.net/?f=%20A%28x%29%20%3D%20%5Cpi%20%5Bf%28x%29%5D%5E2%20%3D%20%5Cpi%20r%5E2%20%3D%20%5Cpi%20%5B3x%5D%5E2%20%3D%209%5Cpi%20x%5E2)
And the volume is given by the following formula:

For our case our limits are x=0 and x=2 so we have this:

And if we solve the integral we got this:
![V= \pi [\frac{x^3}{3}]\Big|_0^{2}](https://tex.z-dn.net/?f=%20V%3D%20%5Cpi%20%5B%5Cfrac%7Bx%5E3%7D%7B3%7D%5D%5CBig%7C_0%5E%7B2%7D)
And after evaluate we got this:
![V=\pi [(\frac{8}{3} )-(\frac{0}{3} )]](https://tex.z-dn.net/?f=%20V%3D%5Cpi%20%5B%28%5Cfrac%7B8%7D%7B3%7D%20%29-%28%5Cfrac%7B0%7D%7B3%7D%20%29%5D)