This can be solved by using the binomial distribution. The probability of guessing correctly is 0.5, and the probability of making a wrong guess is also 0.5.
Hope this helps have a nice day
The only way a linear (line) graph could have more than 2 intercecting points is if the equations were the same like
y=2x+4 and 2y=4x+8
3rd page:
7) (x+1) (x+2)
8) (x+2) (x+3)
9) (x+2) (x+5)
10) (x+2) (x+8)
11) (y+3) (y+12)
25) (3x+4) (x+9)
26) (2x-3) (x-8)
27) (r-2) (5r-13)
28) (2m-5) (m-3)
Since v=4+2t its linear equation in the graph is a straight line. Put t=0,1,2.....give value of v and draw it. For example, if t=-2, v= 0 so the point on XOY axes is A(-2, 0). I hope that this is the answer that you were looking for and it has helped you.