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gavmur [86]
3 years ago
7

What is the variance of the data set? 8, 9, 10, 16, 17

Mathematics
1 answer:
adoni [48]3 years ago
6 0
Mean = (8 + 9 + 10 + 16 + 17) / 5 = 60/5 = 12.

x - mean:

8 - 12 = -4,  -4² = 16

<span>9 - 12 = -3,  -3² = 9
</span>
<span>10 - 12 = -2,  -2² = 4
</span>
<span>16- 12 = 4,  4² = 16</span>

<span>17- 12 = -5,  -5² = 25
</span>
Sum of the squares =   16 + 9 + 4 + 16 +25 = 70

Variance = 70/5 = 14

Variance = 14
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3 years ago
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bezimeni [28]

Answer:

The correct option is;

A. All rhombuses are parallelograms. Parallelograms have 2 pairs of parallel sides. Therefore, all rhombuses have 2 pairs of parallel sides

Step-by-step explanation:

A rhombus is a quadrilateral that has all 4 sides, it has equal opposite angles and perpendicular diagonals that bisect one another  as well as having a pair of opposite parallel sides making it a parallelogram

A rhombus is similar to a parallelogram which also has equal opposite and parallel sided and equal opposite angles and the diagonals of a parallelogram also bisect each other.

4 0
3 years ago
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Katyanochek1 [597]

Write tan in terms of sin and cos.

\displaystyle \lim_{t\to0}\frac{\tan(6t)}{\sin(2t)} = \lim_{t\to0}\frac{\sin(6t)}{\sin(2t)\cos(6t)}

Recall that

\displaystyle \lim_{x\to0}\frac{\sin(x)}x = 1

Rewrite and expand the given limand as the product

\displaystyle \lim_{t\to0}\frac{\sin(6t)}{\sin(2t)\cos(6t)} = \lim_{t\to0} \frac{\sin(6t)}{6t} \times \frac{2t}{\sin(2t)} \times \frac{6t}{2t\cos(6t)} \\\\ = \left(\lim_{t\to0} \frac{\sin(6t)}{6t}\right) \times \left(\lim_{t\to0}\frac{2t}{\sin(2t)}\right) \times \left(\lim_{t\to0}\frac{3}{\cos(6t)}\right)

Then using the known limit above, it follows that

\displaystyle \left(\lim_{t\to0} \frac{\sin(6t)}{6t}\right) \times \left(\lim_{t\to0}\frac{2t}{\sin(2t)}\right) \times \left(\lim_{t\to0}\frac{3}{\cos(6t)}\right) = 1 \times 1 \times \frac3{\cos(0)} = \boxed{3}

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2 years ago
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3 years ago
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