Question

8x^-9+(-3x^-3y-2)(5/x^6y-2)

Answer 1

$8x^{-9}+(-3x^{-3}y^{-2})(\frac{5}{x^6y^{-2}})$

the first step is to deal with the negative exponents, which causes numbers to go to the other side of the fraction

8x^{-9}+(-3x^{-3}y^{-2})(\frac{5}{x^6y^{-2}})

goes to

$\frac{8}{x^9}+(\frac{-3}{x^3y^2})(\frac{5y^2}{x^6})$

now we can simplify the multiplied terms

$\frac{8}{x^9}+(\frac{-15}{x^9})$

Now that we have common bases, we can add the 2 fractions together to get

$\frac{-7}{x^9}$