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Leya [2.2K]
3 years ago
6

8x^-9+(-3x^-3y-2)(5/x^6y-2)

Mathematics
1 answer:
DaniilM [7]3 years ago
8 0

8x^{-9}+(-3x^{-3}y^{-2})(\frac{5}{x^6y^{-2}})

the first step is to deal with the negative exponents, which causes numbers to go to the other side of the fraction

8x^{-9}+(-3x^{-3}y^{-2})(\frac{5}{x^6y^{-2}})

goes to

\frac{8}{x^9}+(\frac{-3}{x^3y^2})(\frac{5y^2}{x^6})

now we can simplify the multiplied terms

\frac{8}{x^9}+(\frac{-15}{x^9})

Now that we have common bases, we can add the 2 fractions together to get

\frac{-7}{x^9}

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