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Leya [2.2K]
3 years ago
6

8x^-9+(-3x^-3y-2)(5/x^6y-2)

Mathematics
1 answer:
DaniilM [7]3 years ago
8 0

8x^{-9}+(-3x^{-3}y^{-2})(\frac{5}{x^6y^{-2}})

the first step is to deal with the negative exponents, which causes numbers to go to the other side of the fraction

8x^{-9}+(-3x^{-3}y^{-2})(\frac{5}{x^6y^{-2}})

goes to

\frac{8}{x^9}+(\frac{-3}{x^3y^2})(\frac{5y^2}{x^6})

now we can simplify the multiplied terms

\frac{8}{x^9}+(\frac{-15}{x^9})

Now that we have common bases, we can add the 2 fractions together to get

\frac{-7}{x^9}

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3 years ago
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1469.5

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8 0
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Read 2 more answers
Y = f(x) = (-2)^x
guapka [62]

Step-by-step explanation: The value of f(x) when x=-1 is 0.5

Therefore

Step-by-step explanation:

Given that y=f(x)=

to find the f(x) when x=-1 :

That is to find f(-1)

Put x=-1 in the given function f(x)=

Therefore

The value of f(x) when x=-1 is 0.5

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