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2 years ago

Find the selling price.

Mathematics

2 answers:

Gnesinka [82]2 years ago

8 0

Answer:

1.$175

2.$128

3.$55

Step-by-step explanation:

40×.25=35

140+35=175

80×.6=48

80+48=128

50×.1=5

50+5=55

V125BC [204]2 years ago

8 0

Answer:

1 87.5

2 49.7

3 0.79

4 700

5 4.8825

6 24

7 10

explanation:

sana makatulong

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The amount of money spent on textbooks per year for students is approximately normal.

Ostrovityanka [42]

Answer:a

$336.04 < \mu < 443.96$

The margin of error will increase

The margin of error will decreases

The 99% confidence interval is $0.4107 < p < 0.4293$

Step-by-step explanation:

From the question we are told that

The sample size $n = 19$

The sample mean is $\= x = \$\ 390$

The standard deviation is $\sigma = \$ \ 120$

Given that the confidence level is 95% then the level of significance is mathematically represented as

$\alpha = 100 - 95$

$\alpha = 5 \%$

$\alpha = 0.05$

Next we obtain the critical value of $\frac{\alpha }{2}$ from the normal distribution table

$Z_{\frac{\alpha }{2} } = 1.96$

The margin of error is mathematically represented as

$E = Z_{\frac{\alpha }{2} } * \frac{\sigma}{\sqrt{n} }$

=> $E = 1.96 * \frac{120}{\sqrt{19} }$

=> $E = 53.96$

The 95% confidence interval is

$\= x - E < \mu < \= x + E$

=> $390 - 53.96 < \mu < 390 - 53.96$

=> $336.04 < \mu < 443.96$

When the confidence level increases the $Z_{\frac{\alpha }{2} }$ also increases which increases the margin of error hence the confidence level becomes wider

Generally the sample size mathematically varies with margin of error as follows

$n \ \ \alpha \ \ \frac{1}{E^2 }$

So if the sample size increases the margin of error decrease

The sample proportion is mathematically represented as

$\r p = \frac{210}{500}$

$\r p = 0.42$

Given that the confidence level is 0.99 the level of significance is $\alpha = 0.01$

The critical value of $\frac{\alpha }{2}$ from the normal distribution table is

$Z_{\frac{\alpha }{2} } = 2.58$

Generally the margin of error is mathematically represented as

$E = Z_{\frac{\alpha }{2} }* \sqrt{ \frac{\r p (1- \r p )}{n} }$

=> $E = 0.42 * \sqrt{ \frac{0.42 (1- 0.42 )}{ 500} }$

=> $E = 0.0093$

The 99% confidence interval is

$\r p - E < p < \r p + E$

$0.42 - 0.0093 < p < 0.42 + 0.0093$

$0.4107 < p < 0.4293$

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3 years ago

Nigel flips a coin 50 times and records whether it lands on heads or tails. What is the experimental probability that the coin w

iren [92.7K]

Hope this helps you..!

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3 years ago

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4a + c =17<br><br> A B C are consecutive numbers.

iris [78.8K]

A=3
B=4
C=5
Substitute 3 in for 'a' in the equation, and 5 in for 'c' in the equation to get 17.

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3 years ago

Tom is buying topsoil for the flower bed shown below. One bag of topsoil covers 15 square meters. How many bags of topsoil does

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Answer:

We need 4 topsoils

Step-by-step explanation:

I think your question is missed of key information that is the area of the flower bed, allow me to add in and hope it will fit the original one.

Please have a look at the attached photo.

My answer:

The flower bed is a triangle with its height is 5 cm and the base length is 12 cm, so we need to find out the area of it:

S = Height*the base length = 5 * 12 = 60 $m^{2}$

So the bags of topsoil does Tom need to cover his flower bed is:

$\frac{Area of the flower bed}{The area of the topsoil }$ = $\frac{60}{15}$ = 4

We need 4 topsoils

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3 years ago

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What is 5.823 rounded to the nearest whole<br> what is 3.147 rounded to the nearest whole

stich3 [128]

Answer:

6 and 3

Step-by-step explanation:

5.8 to the nearest whole is 6

3.147 to the nearest whole is 3

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2 years ago