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3 years ago

Write the point-slope form of an equation of the line through the points (-2, -3) and (-7, 4).

Mathematics

2 answers:

AVprozaik [17]3 years ago

7 0

Answer:

458435464546484845kdnh

ElenaW [278]3 years ago

4 0

Answer:

C. y+3=−7/5(x+2)

Step-by-step explanation:

Line is passing through the points (-2, -3) and (-7, 4).

Slope of line = (-3 - 4)/[-2-(-7)]= (-7)/(-2+7) = - 7/5

Equation of line in the point-slope form is given as with point (-2, -3).

y - (-3) = - 7/5[x - (-2)]

y + 3 = - 7/5(x +2)

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4 years ago

-3x + 3y = 4 -x+ y = 3

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Answer:

No solution

Step-by-step explanation:

-3x + 3y = 4

-x + y = 3

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Move the variable to the right side and change its sign

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-x = 3 - y

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3 years ago

A carnival ride is in the shape of a wheel with a radius of 25 feet. The wheel has 20 cars attached to the center of the wheel.

Vladimir79 [104]

Centre angle will be 360° as its totally a circle.

radius=r=25ft

Angle between two cars=360/20=18°

Arc length=L

$\\ \sf\longmapsto L=\dfrac{\theta}{360}(2\pi r)$

$\\ \sf\longmapsto L=\dfrac{18}{360}(2\pi(25))$

$\\ \sf\longmapsto L=\dfrac{1}{20}(50\pi)$

$\\ \sf\longmapsto L=2.5\pi ft$

Now

Area be A

$\\ \sf\longmapsto A=\dfrac{1}{2}Lr^2$

$\\ \sf\longmapsto A=\dfrac{1}{2}(2.5\pi)(25)^2$

$\\ \sf\longmapsto A=625(2.5)\pi\dfrac{1}{2}$

$\\ \sf\longmapsto A=1562.5\pi/2$

$\\ \sf\longmapsto A=781\pi ft^2=$

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3 years ago