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White raven [17]
3 years ago
15

The rate at which a professional tennis player used carbohydrates during a strenuous workout was found to be 1.7 grams per minut

e. If a line were graphed showing time (in minutes) on the horizontal axis and carbohydrates used (in grams) on the vertical axis, what would be the slope of the line?
How many carbohydrates (in grams) would the athlete use in 40 minutes?

Mathematics
1 answer:
Alex787 [66]3 years ago
8 0

Answer:

<em>m=1.7</em>

<em>C=68 gr</em>

Step-by-step explanation:

<u>Function Modeling</u>

We are given a relationship between the carbohydrates used by a professional tennis player during a strenuous workout and the time in minutes as 1.7 grams per minute. Being C the carbohydrates in grams and t the time in minutes, the model is

C=1.7t

The slope m of the line is the coefficient of the independent variable, thus m=1.7

The graph of C vs t is shown in the image below.

To find how many carbohydrates the athlete would use in t=40 min, we plug in the value into the equation

C=1.7\cdot 40=68\ gr

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Step-by-step explanation:

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The table below shows the ticket rates for whale watching trips offered by Ocean Tours. AgeTicket Price. Under three yearsfree.
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If there are 40 children aged twelve and under and x of them are under three years old, 40 - x aged three twelve years old. From the 92 people that where taken by the company on whale watching trips, 52 are over twelve years old. The equation that best show the total cost, C is
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Minor surgery on horses under field conditions requires a reliable short-term anesthetic producing good muscle relaxation, minim
andreev551 [17]

Answer:

p_v =P(t_{74}    

If we compare the p value and a significance level for example \alpha=0.1 we see that p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, so we can conclude that the true mean it's not significantly less than 20 min.

Step-by-step explanation:

Data given and notation    

\bar X=18.81 represent the average lateral recumbency for the sample    

s=8.4 represent the sample standard deviation    

n=75 sample size    

\mu_o =20 represent the value that we want to test    

\alpha represent the significance level for the hypothesis test.    

t would represent the statistic (variable of interest)    

p_v represent the p value for the test (variable of interest)    

State the null and alternative hypotheses.    

We need to apply a left tailed  test.  

What are H0 and Ha for this study?    

Null hypothesis:  \mu \geq 20  

Alternative hypothesis :\mu < 20  

Compute the test statistic  

The statistic for this case is given by:  

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}} (1)    

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".    

Calculate the statistic    

We can replace in formula (1) the info given like this:    

t=\frac{18.81-20}{\frac{8.4}{\sqrt{75}}}=-1.227

The degrees of freedom are given by:

df=n-1=75-1=74    

Give the appropriate conclusion for the test  

Since is a one side left tailed test the p value would be:    

p_v =P(t_{74}    

Conclusion    

If we compare the p value and a significance level for example \alpha=0.1 we see that p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, so we can conclude that the true mean it's not significantly less than 20 min.

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3 years ago
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Answer:

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Step-by-step explanation:

we are given

\frac{1}{4-7i}

Firstly, we will get rid of imaginary term from denominator

so, we will multiply conjugate to both top and bottom term

\frac{1}{4-7i}=\frac{1\times (4+7i)}{(4-7i)\times (4+7i)}

\frac{1}{4-7i}=\frac{4+7i}{4^2-(7i)^2}

\frac{1}{4-7i}=\frac{4+7i}{16+49}

\frac{1}{4-7i}=\frac{4+7i}{65}

we can also write as

so, we get

\frac{1}{4-7i}=\frac{4}{65}+\frac{7}{65}i

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