3 years ago

What are the zeros of f(x) = x2 - 8x+16?

Mathematics

1 answer:

Stels [109]3 years ago

3 0

Answer:

x=4

Step-by-step explanation:

f(x) = x^2 - 8x+16

Set equal to zero

0 = x^2 -8x +16

Factor

what 2 numbers multiply to 16 and add to -8

-4*-4 = 16

-4+-4 = -8

0= (x-4)(x-4)

Using the zero product property

x-4 = 0 x-4 =0

x=4 x=4

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