Answer:
- f[1] = 3
- f[n] = 2·f[n-1] +4
- 108
Step-by-step explanation:
We observe that first differences of the given numbers are ...
10 -3 = 7
24 -10 = 14
52 -24 = 28
That is, each difference is 2× the previous one. This suggests an exponential relation that has a base of 2.
We notice that doubling a term doesn't give the next term, but gives a value that is 4 less than the next term. So, we can get the next term by doubling the previous one and adding 4.
Then our recursive relation is ...
f[1] = 3 . . . . the first term
f[n] = 2×f[n-1] +4 . . . . double the previous term and add 4
The next term is 2·52 +4 = 108.
