4.
h(f(x)=h(2x-1)=
(2x-1)^2+1=
4x²-4x+1+1=
4x²-4x+2
5.
f(f(x))=2(2x-1)-1=4x-2-1=4x-3
6.
f o g (x)=f(g(x))
h o g (x)=h(g(x))=
(3x)^2+1=
9x²+1
Sn=sum of the n terms of the geometric sequence.
a= the first term
r=the common ratio
n=numbers of terms.
Sn=a[(1-r^n)/(1-r)]
In this case:
a=-3
r=a₂/a₁=15/-3=-5
n=9
S₉=-3[(1-(-5)⁹) / (1-(-5))=
S₉=-3(1+1953125)/6)=
S₉=-3(1953126/6)=
S₉=-3(325521)
S₉=-976563
Answer: A. -976563
Answer:
Polygon q’s area is one fourth of polygon p’s area
Step-by-step explanation:
we know that
If two figures are similar, then the ratio of its areas is equal to the scale factor squared
Let
z-----> the scale factor
x-----> polygon q’s area
y-----> polygon p’s area
so

In this problem we have

substitute



therefore
Polygon q’s area is one fourth of polygon p’s area
Answer:
24
Step-by-step explanation:
Given that:
Total number of members who race = 18
Ratio of racers to divers = 6 : 2
To find:
Total number of members of the team = ?
Solution:
Given the ratio = 6 : 2
As per the ratio given, we can let the number of racers = 
and
As per the ratio given, we can let the number of divers = 
As the swim team members can either race or dive, we can say that:
Total number of members on the team = Number of racers + Number of divers
Total number of members on the team = 
As per the question statement, we are given that:

Therefore, total number of team members = 8
3 = <em>24</em>
Answer:
12 and square
Step-by-step explanation: