Answer:
Na
Explanation:
Because sodium loses one electron and becons Na+ and sodium oxidizes
Los of electron is oxidation
Answer:
We're asked to find the molar concentration of the
NaCl
solution given some titration data.
Let's first write the chemical equation for this reaction:
NaOH
(
a
q
)
+
HCl
(
a
q
)
→
NaCl
(
a
q
)
+
H
2
O
(
l
)
Using the molarity equation, we can find the number of moles of
HCl
that reacted:
molarity
=
mol solute
L soln
mol solute
=
(
molarity
)
(
L soln
)
mol HCl
=
(
0.105
mol
L
)
(
0.0250
L
)
=
0.00263
mol HCl
(volume converted to liters)
Now, using the coefficients of the chemical reaction, we can determine the number of moles of
NaOH
that reacted:
0.00263
mol HCl
(
1
l
mol NaOH
1
mol HCl
)
=
0.00263
mol NaOH
Lastly, we'll use the molarity equation (using given volume of
NaOH soln
) again to determine the molarity of the sodium hydroxide solution:
molarity
=
mol solute
L soln
M
NaOH
=
0.00263
l
mol
0.315
l
L
=
0.00833
M
(volume converted to liters)
Answer:
5.64x10⁻³ g of S₈S₈
Explanation:
We consider mm as milimolal
Milimolal = molal . 1000
Molal are the moles of solute contained in 1kg of solvent.
Solute → Sulfur (S₈S₈)
Solvent → naphthalene
0.11 mm / 1000 = 1.1x10⁻⁴ molal
moles of solute / kg of solvent = 1.1x10⁻⁴ molal
moles of solute / 0.1 kg of solvent = 1.1x10⁻⁴ molal
moles of solute = 1.1x10⁻⁴ m/kg . 0.1kg → 1.1ₓ10⁻⁵ moles
Molar mass S₈S₈ = 512.96 g/m
1.1ₓ10⁻⁵ mol . 512.96 g/m = 5.64x10⁻³ g
Answer:
NaH(s) + H2O(l) ------> NaOH(aq) + H2(g)
2Al(s) + 3Cl2(g) -----> 2AlCl3(s)
Explanation:
The rule of thumb in balancing chemical reaction equation is that the number of atoms of each element on the reactant side must be the same as the number of atoms of the same element on the product side. Only then can any reaction equation be seen as balanced.
For example there are two aluminum atoms on both sides of the reaction equation and six chlorine atoms on both sides of the reaction equation. Hence the reaction equation is balanced.
