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zhannawk [14.2K]
3 years ago
6

The value equal the sum of the protons and neutrons in the nucleus of an atom

Chemistry
1 answer:
Roman55 [17]3 years ago
6 0

The Atomic Number should be your answer, although I am not completely sure.

You might be interested in
PLEASE HELP!!!
algol [13]
Question 1 answer: A

Question 2 answer: H

Question 3 answer: J

Question 4 answer: T
8 0
4 years ago
6. What is the pressure of 0.60 moles of a gas if its volume is 10.0 liters at 35.0°C?
denis-greek [22]

Answer: The pressure inside the cylinder will be 1.5 atm. The pressure can be calculated using the Ideal Gas Equation which relates the pressure, volume, temperature, and amount of gas to each other.  

Further Explanation

The Ideal Gas Equation is:  

PV = nRT

where:

P - pressure (in atm)

V - volume (in L)

n - amount of gas (in moles)

R - universal gas constant 0.08206 \frac{L-atm}{mol-K}

T - temperature (in K)

In the problem, we are given the values:

P = ?

V = 10.0 L (3 significant figures)

n = 0.60  moles  ( 2 significant figures)

T = 35.0 degrees Celsius (3 significant figures)

We need to convert the temperature to Kelvin before we can use the Ideal Gas Equation. The formula to convert from degree Celsius to Kelvin is:

Temperature \ in \ Kelvin = Temperature\ in \ Celsius \ + \ 273.15

Therefore, for this problem,

Temperature\ in \ K = 35.0 +273.15\\Temperature\ in \ K = 308.15

Solving for P using the Ideal Gas Equation:

P = \frac{nRT}{V} \\P = \frac{(0.60\ mol) \ (0.08206 \ \frac{L-atm}{mol - K}) \ (308.15\ K) \ }{10.0 \ L} \\P = 1.51\ atm

The least number of significant figures is 2,  therefore, the final answer must have only 2 significant figures.

Learn More

1. Learn more about Boyle's Law brainly.com/question/1437490  

2. Learn more about Charles' Law brainly.com/question/1421697

3. Learn more about Avogadro's Law brainly.com/question/1964205

Keywords: Ideal Gas Law, Gas Pressure

7 0
3 years ago
Balance the following chemical equations
nexus9112 [7]

Explanation:

  1. 2Na + I₂ → 2NaI
  2. 2KClO₃ → 2KCl + 3O₂
  3. K₃PO₄ + 3HCl → 3KCl + H₃PO₄

6 0
3 years ago
Name 2 physical properties that would allow differentiation between copper, lead and iron shot.
Olegator [25]

Answer:

Two physical properties that would allow differentiation between copper, lead and iron shot are - <u>Color</u> and <u>Density </u>

<u>COPPER -</u> <u>Color -</u> Copper has a<u> reddish brown color .</u>

                <u> Density -</u> Density of copper is<u> 8.96 </u>g/cm^{3}<u></u>

<u>LEAD </u>- <u>Color -</u> Lead is <u>grey</u> in color.

           <u>Density</u> - Density of Lead is <u>11.34</u>g/cm^{3}<u />

<u>IRON SHOT -</u> <u>Color-</u>  Iron shot is in <u>grey color with extra shine .</u>

                     <u>  Density -</u> Density of iron shot is <u>10.49 </u>g/cm^{3}

Explanation:

COPPER- Copper (Cu) is a reddish, highly ductile metal that belongs to Group 11 (Ib) of the periodic table and is a particularly excellent conductor of electricity and heat. Copper is found in nature in its free metallic state.

LEAD- Lead (Pb) is a soft, silvery white or grayish metal in Periodic Group 14 (IVa). Lead is a weak conductor of electricity and is very malleable, ductile, and thick. Lead, which has been known since antiquity and is considered the oldest of metals by alchemists, is extremely durable and corrosion-resistant, as evidenced by the continued use of lead water pipes constructed by the ancient Romans.

IRON SHOT - Small round iron balls used as projectiles are known as iron shot. Balance scales are used with simple weights. Iron balls are used in the shot put competition.

<u>Hence , the differentiation is mentioned in the above answer.</u>

4 0
3 years ago
Q2.
Serga [27]

Answer:

266 liters Carbon iv oxide will be formed

Explanation:

The first thing we need to do here is to calculate the number of moles of oxygen reacted.

This can be calculated using the ideal gas equation;

Mathematically;

PV = nRT

From the question;

P = pressure = 10.5 atm

V = volume = 400 liters

n = number of moles = ?

T = temperature = 125 + 273 = 398K

R = molar gas constant = 0.0821 L•atm•K^-1•mol^-1

Substituting these values, we have ;

n = PV/RT

n = (10.25 * 400)/(398 * 0.0821) = 125 moles

From the question;

15 moles oxygen gave 10 moles CO2

125 moles oxygen will give x moles CO2

x = (125 * 10)/15 = 83 moles

Now, we want to know the volume of CO2, present in 83 moles using the given reaction conditions.

Mathematically;

PV = nRT

V = nRT/P

= (83 * 0.0821 * 398)/10.25 = 265.65 which is approximately 266 Liters

4 0
3 years ago
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